Answer:
Step-by-step explanation:
Hi there!
α, β, γ are the zeroes of the polynomial x³ + px² + qx + 2
Then,
• α + β + γ = - p ---(i)
• αβ + βγ + γα = q. ---(ii)
• αβγ = - 2. ---(iii)
We're Given :-
αβ + 1 = 0 Or αβ = - 1
Substitute " αβ = - 1 " in eqn. (iii) :-
(- 1) γ = - 2
γ =
![\dfrac {- 2}{- 1}](https://tex.z-dn.net/?f=%5Cdfrac%20%7B-%202%7D%7B-%201%7D)
γ = 2
Now. Accr'ding to the question :-
2p + q + 5 = - 2 (α + β + γ) + (αβ + βγ + γα) + 5
= - 2 (α + β + γ) + (αβ + [ γ (β + α) ] + 5
= - 2 (α + β + 2) + [ - 1 + 2 ( α + β ) ] + 5
= - 2α - 2β - 4 - 1 + 2α + 2β + 5
= 5 - 5
= 0
∴ 2p + q + 5 = 0
~ Hope it helps!
Answer:
Use google
Step-by-step explanation:
Answer:
B I think C is wrong and A is wrong
Answer:
(0, 1 )
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given
y - 4x = 1 ( add 4x to both sides )
y = 4x + 1 ← in slope- intercept form
with c = 1
the coordinates of the y- intercept are (0, 1 )