PLEASE PLEASE PLEASE HELP ME WITH THIS ASAP

If an object has a mass of 15 g and a volume of 3 mL what is its density

Annette [7]

Answer:

Given the mass of the object = 15g

Given the volume of the object = 3 mL

Density = ?

Step-by-step explanation:

We have two values of an object that is mass of the object and volume of the object. Now we are required to find the Density of the object. In order to find the density of the object, we have to divide the given mass with the given volume. Below is the calculation of the density.

Density = Mass / Volume

Density = 15g / 3 mL

Density = 5 g/ml

7 0

3 years ago

Mr. Hughes gave 5/14

kow [346]

Answer:

His savings were of $4,200.

Step-by-step explanation:

Mr. Hughes gave 5/14 of his savings to his son, 2/3 of the remainder to his daughter, and the rest to his wife:

This means that the son and daughter amount is:

$\frac{5}{14} + \frac{2}{3}(\frac{9}{14})$

As $\frac{9}{14}$ is the remained that his son did not get. So

$\frac{5}{14} + \frac{2}{3}(\frac{9}{14}) = \frac{15}{42} + \frac{18}{42} = \frac{33}{42}$

Fraction his wife got:

$1 - \frac{33}{42} = \frac{42}{42} - \frac{33}{42} = \frac{9}{42}$

If his wife got $900, what were his savings?

Total savings are x, wife got $\frac{9}{42}$ of x. So

$\frac{9x}{42} = 900$

$9x = 900*42$

$x = \frac{900*42}{9}$

$x = 100*42$

$x = 4200$

His savings were of $4,200.

5 0

2 years ago

A short-wave radio antenna is supported by two guy wires, 150 ft and 180 ft long. Each wire is attached to the top of the antenn

Dafna1 [17]

The distance between the anchor points of the two guy wires holding radio antenna is 181 feet (to the nearest foot)

<h3>How to determine the distance between the two anchor points of the guy wire</h3>

The problem will be solved using SOH CAH TOA

let the distance between the 150 ft long guy wire and the radio antenna be x

let the distance between the 180 ft long guy wire and the radio antenna be y

cos 65° = x / 150

x = cos 65° * 150

x = 63.39 ft

The height of the antenna

sin 65° = height of antenna / 150

height of antenna = sin 65 * 150

height of antenna = 135.95

using Pythagoras theorem

(length of guy wire)² = (height of the antenna)² + (anchor distance)²

(anchor distance)² = 180² - 135.95²

anchor distance = √(180² - 135.95²)

anchor distance = 117.97

The anchor points distance apart

= 63.39 + 117.97

= 181 (to the nearest foot)

Learn more on Pythagoras theorem here:

brainly.com/question/29241066

#SPJ1

4 0

1 year ago

Use the drop-down menu to complete each statement. The amount of money you earn by working is your . The percentage of people ac

Galina-37 [17]

The correct answers are:

- Wage/salary;

- Active job seekers;

The amount of money you earn by working is your wage or salary. The difference being that the wage represents the money you get paid on hourly, weekly, or monthly basis, while the salary is what you earn in year. The wages/salaries vary a lot, some being very high, some being modest, some very high, depending on the type of job, type of economy, as well as the qualifications of the worker.

The percentage of people that are actively looking for job is called active job seekers. The active job seekers can be people that are unemployed, but also people that re employed but want to work something or somewhere else. While some people struggle to find jobs and would accept almost anything, other people want to constantly progress, thus they are not satisfying with a job where they do not progress, so they seek for new challenges and opportunities.

7 0

3 years ago

Read 2 more answers

Allan drew a polygon with 4 sides and 4 angles. All four sides are equal. None of the angles are right angles. What figure did A

Lady_Fox [76]

Answer: The figure drawn by Alan is a rhombus.

Step-by-step explanation:

Given: Allan drew a polygon with 4 sides and 4 angles with two properties:-

All four sides are equal.
None of the angles are right angles.

We know that only a rhombus is a flat shape with 4 equal straight sides and 4 angles .All sides have equal length. Its angles need not to be right angle.

Therefore, the figure drawn by Alan is a rhombus.

8 0

3 years ago

Read 2 more answers