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3 years ago

You roll four six-sided die. Find the probability that exactly three of the dice are odd.

Mathematics

2 answers:

strojnjashka [21]3 years ago

5 0

Answer:

9/24 or 3/8

Step-by-step explanation:

3/6 (3 out of the 6 sides are odd)

3/4 (3 out of 4 die)

Multiply together

3/6 * 3/4= 9/24

so 9/24 is the answer... you can simplify it to 3/8.

ur welcome :)

s344n2d4d5 [400]3 years ago

3 0

Answer:

3/8

Step-by-step explanation:

There is a 1/2 probability one die will be odd because 1, 3, and 5 are the only possible odd numbers.

Since you want 3/4 of the dice to be odd, you multiply 1/2 by 3/4 to get 3/8.

I believe it is 3/8.

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PLEASE HELP WITH ALGEBRA!!!

ExtremeBDS [4]

Answer: aₙ = 3 + 4ⁿ⁻¹

So the formula would be:

aₙ = 3 + 4ⁿ⁻¹

Where a₁ = 3

Common Ratio (r) = 4

And n = the term number that needs to be found out

Step-by-step explanation:

Let's check if the answer is right:

To find the 1st number in the term we can substitute 1 in for n in the equation:

a₁ = 3 + 4¹⁻¹

a₁ = 3 + 4⁰

a₁ = 3 + 1

a₁ = 4

And if going back and checking the first number in the sequence given is indeed 4, therefore this equation is correct

Hope this helps!

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3 years ago

Find a polynomial equation that has roots of -2 and double root 3

lbvjy [14]

Answer:

x³ + 2x² -3x +6

Step-by-step explanation:

We need to find the polynomial whose roots are ,

-2 , √3 and √3.

Say of we have zeroes as , α , β and γ , then the polynomial is ,

=> p(x) = k[ (x - α ) ( x - β) ( x - γ) ]

where k is constant. Substituting the respective values , we have ,

=> p(x) = k [ ( x - (-2)) ( x - √3) ( x -√3)]

=> p(x) = k[ (x+2)(x² - 3)]

=> p(x) = k[ x(x² - 3) + 2(x² - 3) ]

=> p(x) = k[ x³ - 3x + 2x² - 6 ]

=> p(x) = k[ x³ + 2x² - 3x - 6 ]

<h3>Hence the cubic polynomial is x³ + 2x² - 3x + 6 .</h3>

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julia-pushkina [17]

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Svetach [21]

Answer:

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and same thing in the first trangle

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Murrr4er [49]

Answer:

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