Answer:
Holy bloop you gotta learn
Step-by-step explanation:
you dumb
go to school
and learn
In this relation we have two ordered pairs:
( 5, 7 ) and ( 5, 8 )
For x = 5 : f ( x ) = 7 and also for x = 5, f ( x ) = 8. This is not possible for a function.
Answer:
b ) No. The relation is not a function.
Answer: 3p² + q² - 5pq - 10 < 0
<u>Step-by-step explanation:</u>
p² - q² + 2pq < -2p² - 2q² + 7pq + 10
since you didn't specify what to solve for, move everything from the right side to the left side of the inequality symbol using inverse operations.
(p² + 2p²) + (- q² + 2q²) + (2pq - 7pq) + (- 10) < 0
3p² + q² + -5pq + -10 < 0
3p² + q² - 5pq - 10 < 0
H < 1 I think that's the answer
