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skelet666 [1.2K]
3 years ago
10

Which expression is equivalent to

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0

Answer:

C

Step-by-step explanation:

When 3 is squared, it becomes 9. That means that both A and B are incorrect.

The powers on u and v are doubled not added to become u^6 and v^8 so that makes C the only possible answer.

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What is the simplified form of (x – 2)(2x +3)? Use the Distributive Property. (1 point)
Alecsey [184]
1. 2x2 – x – 6
2. 12x2 – x –6
3. 4p2 – 18p + 8
7 0
3 years ago
If twice a number is subtracted from 11, the result is 4 more than the number. What is the number?
Flauer [41]

Let the number = x.

So 2 times x subtracted from 11 is written as 11-2x

The result is 4 more than the number is written as 4 +x

Now you have 11-2x = 4 + x

We can now solve for x.

Add 2x to each side:

11 = 4 + 3x

Subtract 4 from each side:

7 = 3x

Divide both sides by 3:

x = 7/3

4 0
3 years ago
A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean \mu and standard deviation \sigma, we have these following probabilities

Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827

Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545

Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So \mu = 53, \sigma = 11

So:

Pr(53-11 \leq X \leq 53+11) = 0.6827

Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545

Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973

-----------

Pr(42 \leq X \leq 64) = 0.6827

Pr(31 \leq X \leq 75) = 0.9545

Pr(20 \leq X \leq 86) = 0.9973

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have Pr(31 \leq X \leq 75) = 0.9545 = 0.9545 subtracted by Pr(42 \leq X \leq 64) = 0.6827 is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

P = {0.9545 - 0.6827}{2} = 0.1359

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0
3 years ago
In an architecture class the students built a scale model of an office building. If the scale is 1 in. = 12 feet and the model i
iogann1982 [59]

Answer:

102 feet tall

Step-by-step explanation:

12 multiplied by 8 1/2 to get 102

7 0
3 years ago
Read 2 more answers
Bill works as a waiter and is keeping track of the tips he earns daily. About how much does Bill have to earn in tips on Sunday
xeze [42]

Answer:

So $28

Step-by-step explanation:

14+12+13+25+32+30=126

126+28=154/7=22

5 0
3 years ago
Read 2 more answers
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