Answer:
<em>The answer to your question is Domain is 2. Then the range is 4..</em>
Have a wonderful day, and I hopes it helps! I wasn't exactly sure about my answer, but I'm sure that it is right! ^^'
Y=-x/2+9
y=x+7
If we solve this system of equations, we can find the solution to the following system of equation.
we can solve this system of equation by equalization method.
-x/2+9=x+7
lowest common multiplo=2
-x+18=2x+14
-3x=-4
x=-4/-3=4/3
y=x+7=4/3 + 7=(4+7*3)/3=25/3
The solution is (4/3, 25/.3)
answer: Line y=-x/2+9 intersects line y =x+7
Answer:
89 is the maximum number of guests that can be invited within budget .
Step-by-step explanation:
The cleaning charges = $55
Total budget available = $3350
Cost per guest = $37
Now, actual budget available for guest = Total budget - Cleaning Fee
= $3350 - $ 55 = $3,295
Now, cost per head =$ 37
So, number of guests (n) possible in the budget
⇒ n = (Total guest Budget)/ Cost per head
= $3,295 / $37 = $89.05
or, n = $89.05
So, 89 is the maximum number of guests that can be invited within budget .
Answer:
8
Step-by-step explanation:
Two different approaches:
<u>Method 1</u>
Apply radical rule √(ab) = √a√b to simplify the radicals:
√98 = √(49 x 2) = √49√2 = 7√2
√50 = √(25 x 2) = √25√2 = 5√2
Therefore, (√98 - √50)² = (7√2 - 5√2)²
= (2√2)²
= 4 x 2
= 8
<u>Method 2</u>
Use the perfect square formula: (a - b)² = a² - 2ab + b²
where a = √98 and b = √50
So (√98 - √50)² = (√98)² - 2√98√50 + (√50)²
= 98 - 2√98√50 + 50
= 148 - 2√98√50
Apply radical rule √(ab) = √a√b to simplify radicals:
√98 = √(49 x 2) = √49√2 = 7√2
√50 = √(25 x 2) = √25√2 = 5√2
Therefore, 148 - 2√98√50 = 148 - (2 × 7√2 × 5√2)
= 148 - 140
= 8
