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Gemiola [76]
3 years ago
10

Solve the equation and show your work please! 3(2y - 0.3) = 19.4 - y

Mathematics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

y=2.9

Step-by-step explanation:

3(2y - 0.3) = 19.4 - y

6y-0.9=19.4

6y+y-0.9=19.4

6y+y=19.4+0.9

7y=19.4+0.9

7y=20.3

7y/7=20.3/7 (divid each one by seven. that's what /7 means)

y=2.9

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What is the length of segment BD
lisabon 2012 [21]

Answer:  The length of BD is 2.4

Step-by-step explanation:  BD is a leg of a right triangle, so use the

Pythagorean Theorem  a² + b² = c²  

BC is the hypotenuse here, so that is c = 3

We can use the segment CD as side b = 1.8

We will call BD side a, and solve to find that length.

a² + (1.8)² = 3²   Square the known values of b and c

 a² + 3.24 = 9     Subtract 3.24 from both sides.

a² = 9 - 3.24     Simplify

a²  =  5.76          Find the square root of both sides (Calculator time!)

a = 2.4

5 0
3 years ago
Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
prohojiy [21]

If you substitute each ordered pair for x and y the only ordered pair that works is (0,-3) .

6 0
3 years ago
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What is 2 1/3 multiplied by 5 1/3 as a mixed number or fraction
snow_tiger [21]

First we must convert the mixed numbers to the improper fractions:

2\dfrac{1}{3}=\dfrac{2\cdot3+1}{2}=\dfrac{7}{3}\\\\5\dfrac{1}{3}=\dfrac{5\cdot3+1}{3}=\dfrac{16}{3}


2\dfrac{1}{3}\cdot5\dfrac{1}{3}=\dfrac{7}{3}\cdot\dfrac{16}{3}=\dfrac{7\cdot16}{3\cdot3}=\dfrac{112}{9}=\dfrac{108+4}{9}=12\dfrac{4}{9}\\\\Answer:\ \boxed{2\dfrac{1}{3}\cdot5\dfrac{1}{3}=12\dfrac{4}{9}}

6 0
3 years ago
Find the length of arc XPY.
KiRa [710]

Answer:

Arc length XPY =28.26 m.

Step-by-step explanation:

Given : A circle with two arc XY and XPY and radius 6 m.

To find  : Arc length XPY.

Solution : We have given that arc XY and XPY .

Radius = 6 m.

Central angle formed by arc XPY = 360 - 90 = 270.

Arc length = 2 *pi* r ( \frac{central\ angle}{360}.

Plugging the values

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6 0
4 years ago
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For what value of k, the zeroes of x2 + kx + 12 will differ by 1?
asambeis [7]

Let <em>a</em> and <em>b</em> be the zeroes of <em>x</em>² + <em>kx</em> + 12 such that |<em>a</em> - <em>b</em>| = 1.

By the factor theorem, we can write the quadratic in terms of its zeroes as

<em>x</em>² + <em>kx</em> + 12 = (<em>x</em> - <em>a</em>) (<em>x</em> - <em>b</em>)

Expand the right side and equate the coefficients:

<em>x</em>² + <em>kx</em> + 12 = <em>x</em>² - (<em>a</em> + <em>b</em>) <em>x</em> + <em>ab</em>

Then

<em>a</em> + <em>b</em> = -<em>k</em>

<em>ab</em> = 12

The condition that |<em>a</em> - <em>b</em>| = 1 has two cases, so without loss of generality assume <em>a</em> > <em>b</em>, so that |<em>a</em> - <em>b</em>| = <em>a</em> - <em>b</em>.

Then if <em>a</em> - <em>b</em> = 1, we get <em>b</em> = <em>a</em> - 1. Substitute this into the equations above and solve for <em>k</em> :

<em>a</em> + (<em>a</em> - 1) = -<em>k</em>   →   2<em>a</em> = 1 - <em>k</em>   →   <em>a</em> = (1 - <em>k</em>)/2

<em>a</em> (<em>a</em> - 1) = 12   →   (1 - <em>k</em>)/2 • ((1 - <em>k</em>)/2 - 1) = 12

→   (1 - <em>k</em>)²/4 - (1 - <em>k</em>)/2 = 12

→   (1 - <em>k</em>)² - 2 (1 - <em>k</em>) = 48

→   (1 - 2<em>k</em> + <em>k</em>²) - 2 (1 - <em>k</em>) = 48

→   <em>k</em>² - 1 = 48

→   <em>k</em>² = 49

→   <em>k</em> = ± √(49) = ±7

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