Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!
Answer:
I believe it is distributive because you are finding the products. Yes, the numbers are mixed up but the parenthesis often involve distributive property.
Hm, it seems like his answer is off. The image is what I got.
Answer:
i think they are y and (x,y)
Answer:
B.point V i am positive
Step-by-step explanation:
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