Minha says triangle A with angles measuring 34 ° and 57 ° is similar to triangle B with angles measuring 57 ° and 89 ° . What Mi
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Ada is <u>incorrect</u>, as the length of diagonal SQ is not two times the length of diagonal OM. The theorem used is the Pythagoras Theorem.
For Rectangle PQRS:-
By Pythagoras Theorem, in right triangle PQS,
SQ² = PQ² + PS²,
or, SQ² = 8² + 16² sq. inches,
or, SQ² = 64 + 256 sq. inches,
or, SQ = √320 sq. inches,
or, SQ = 8√5 inches.
Thus, the length of diagonal SQ, of rectangle PQRS is 8√5 inches.
For Square LMNO:-
By Pythagoras Theorem, in right triangle LMO,
OM² = LM² + LO²,
or, OM² = 8² + 8² sq. inches,
or, OM² = 64 + 64 sq. inches,
or, OM = √128 sq. inches,
or, OM = 8√2 inches.
Thus, the length of diagonal OM, of square LMNO is 8√2 inches.
We know that 2*OM ≠ SQ, as 2*8√2 ≈ 8√5.
Thus, Ada is <u>incorrect</u>, as the length of diagonal SQ is not two times the length of diagonal OM. The theorem used is the Pythagoras Theorem.
Learn more about the diagonal of square and rectangle at
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Answer:
The correct expression for the perimeter is
see the explanation
Step-by-step explanation:
The complete question in the attached figure
Let
L ----> the length of rectangle
W ---> the width of rectangle
we know that
The perimeter of rectangle is equal to
In this problem we have
substitute the values
Simplify
so
Michelle didn't multiply the sum of length and width by 2
