Question

0%7D%20%5Cgeq%20%5Csqrt%7B%20b%5E%7B2%7D%2Bbc%2Bc%5E%7B2%7D" id="TexFormula1" title="\sqrt{a^{2}+ab+b^{2}} +\sqrt{ a^{2}+ac+c^{2} } \geq \sqrt{ b^{2}+bc+c^{2}" alt="\sqrt{a^{2}+ab+b^{2}} +\sqrt{ a^{2}+ac+c^{2} } \geq \sqrt{ b^{2}+bc+c^{2}" align="absmiddle" class="latex-formula">

Answer 1

Answer:

Solution given:

$\sqrt{a^{2}+ab+b^{2}} +\sqrt{a^{2}+ac+c^{2}}+ \sqrt{ b^{2}+bc+c^{2}}$

$\sqrt{(a+b)²} +\sqrt{ (a+c)² }+\sqrt{(b+c)²}$

a+b+a+c+b+c

2a+2b+2c

2(a+b+c)