Answer:
7
Step-by-step explanation:
To find distance on a number line you add and 2+5=7
Answer:
Periodic
Step-by-step explanation:
Because the terms repeat, this is a periodic sequence.
The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
Expressions equivalent can be:
-2(5c)
-2*-5c
=10c
Answer:
b = y-intercept; The equation is y = mx + b. The x and y variables remain as letters, but m and b are replaced by numbers (ex: y = 2x + 4, slope = 2 and y-intercept = 4). The following video will show a few examples of understanding how to use the slope and intercept from an equation.
Vertex (4, -13) y = x^2 - 8x + 3 x-coordinate of vertex: x = -b/(2a) = 8/2 = 4 y-coordinate of vertex: y(4) = 16 - 32 + 3 = -13 Vertex (4, -13) To find y-intercepts, make x = 0 --> y = 3 To find x-intercepts, solve the quadratic equation y = 0 Use the improved quadratic formula D = d^2 = b^2 - 4ac = 64 - 12 = 52 --> d = +- 2sqrt13 There are 2 x-intercepts (2 real roots): x = -b/(2a) +- d/(2a) = 8/2 +- (2sqrt13)/2 = 4 +- sqrt13 graph{x^2 - 8x + 3 [-40, 40, -20, 20]}
Step-by-step explanation:
