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Bezzdna [24]
3 years ago
8

Please help me please​

Mathematics
1 answer:
krok68 [10]3 years ago
7 0

Answer:

y=1

10/5=2

Step-by-step explanation:

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To write 1.65 × 102 in standard notation, move the decimal point two places to the left, true or false?
ivann1987 [24]
False. If you want to make 1.65 × 10to the power of 2 you would move it right two spots. Now if it was 1.65×10-2 then you would move it to the left.
5 0
3 years ago
Which expression is equivalent to 6–3?
Bond [772]

Your question is not well presented. See complete question below

Which expression is equivalent to 6^{-3}?

A) –63

B) 36

C) \sqrt[3]{6}

D) (\frac{1}{6} )^3

Answer:

The equivalent of 6^{-3 is (\frac{1}{6} )^3

Step-by-step explanation:

Given

Expression: 6^{-3}

Required:

Find the Equivalent Expression

To find the equivalent of this expression, we make use of law of indices.

One of the laws of indices states that

a^-b = \frac{1}{a^b}

If we apply this law to the expression above (6^{-3})

By comparison a = 6 and b = 3.

So, 6^{-3} becomes

6^{-3} = \frac{1}{6^3}

Simplifying further;

\frac{1}{6^3} = \frac{1}{6 * 6 * 6}

This can also be written as

\frac{1}{6^3} = \frac{1*1*1}{6 * 6 * 6}

By splitting the above expression; we have that

\frac{1}{6^3} = \frac{1}{6} * \frac{1}{6} * \frac{1}{6}

Multiplication law of indices states that;

a * a * a = a³. (Because they have the same base of a)

So, \frac{1}{6} * \frac{1}{6} * \frac{1}{6} can then be written as (\frac{1}{6} )^3

Hence,  \frac{1}{6^3} = (\frac{1}{6} )^3

So, the equivalent of 6^{-3} is (\frac{1}{6} )^3

7 0
3 years ago
What is the value of the expression
Gelneren [198K]

Answer:32

Step-by-step explanation: First you do 4×4×4×

=64 then you divide by 2.. 64÷2=32

8 0
3 years ago
Read 2 more answers
Find the general solution of the following equation: y'(t) = 3y -5
Anton [14]

Answer:

The general solution of the equation is y = \frac{A}{3}e^{3t} + 5

Step-by-step explanation:

Since the differential equation is given as y'(t) = 3y -5

The differential equation is re-written as

dy/dt = 3y - 5

separating the variables, we have

dy/(3y - 5) = dt

dy/(3y - 5) = dt

integrating both sides, we have

∫dy/(3y - 5) = ∫dt

∫3dy/[3(3y - 5)] = ∫dt

(1/3)∫3dy/(3y - 5) = ∫dt

(1/3)㏑(3y - 5) = t + C

㏑(3y - 5) = 3t + 3C

taking exponents of both sides, we have

exp[㏑(3y - 5)] = exp(3t + 3C)

3y - 5 = e^{3t}e^{3C}        

3y - 5 = Ae^{3t}                A = e^{3C}

3y = Ae^{3t} + 5    

dividing through by 3, we have

y = \frac{A}{3}e^{3t} + 5

So, the general solution of the equation is y = \frac{A}{3}e^{3t} + 5

3 0
4 years ago
If the cost of 8 pizzas is $74, what is the cost per pizza? Use a proportion to solve.
Angelina_Jolie [31]

Answer:

9.25

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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