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lawyer [7]
3 years ago
15

An animal starts from rest and accelerates to its top speed in 7 seconds. It continues at this speed for 9 seconds and then slow

s to a stop in a further 4 seconds. Calculate the total distance that the animal travelled​
Mathematics
1 answer:
Aliun [14]3 years ago
5 0

Answer:

hggffffxdfffdsddfdohgfffdedss

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Fb+3b=d what does d equal
Sedbober [7]

Answer:

it can`t be solved unless you have an integer in place of F and B

otherwise this can`t be solved

6 0
3 years ago
Read 2 more answers
Find the missing values of the variables. The diagram is not to scale.
julsineya [31]

X=93 degrees

Y=74 degrees

3 0
3 years ago
Match each function with the corresponding function formula when h(x) = 2 – 2x and g(x) = –2 x + 2.
Minchanka [31]

the correct functions are

h(x) = 3x + 2

g(x) = 2^x

proceed to calculate the different values ​​of K (x)

case 1) k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + 2]-----------> is the option 4. k(x) = 2^(3x + 2 )

case 2) k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+2--------> is the option 1.) k(x) = 2^x + 3x + 4


case 3)k(x) = g(x) - h(x)

k(x) = [2^x]-[3x + 2]=2^x-3x-2--------> is the option 2.) k(x) = 2^x - 3x - 2

4 0
3 years ago
A biologist is studying adult lobsters. He takes one from its tank and measures its mass. Which is most likely the measure he re
WARRIOR [948]

The weight of an adult lobster i 1lb i hope this helps i personally think it would be (C) 1.14 kg because 1.14 kg is 2.51327 that is the closest weight to an adult lobster


5 0
3 years ago
Solve by using the square root method<br> (x-3)2 +4=125
AveGali [126]

Answer:

x= 127/2

Step-by-step explanation:

Let's solve your equation step-by-step.

(x−3)(2)+4=125

Step 1: Simplify both sides of the equation.

(x−3)(2)+4=125

(x)(2)+(−3)(2)+4=125(Distribute)

2x+−6+4=125

(2x)+(−6+4)=125(Combine Like Terms)

2x+−2=125

2x−2=125

Step 2: Add 2 to both sides.

2x−2+2=125+2

2x=127

Step 3: Divide both sides by 2.

2x/2 = 127/2

x=127/2

Please mark brainliest :)

3 0
3 years ago
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