2 years ago

I have to solve this system equation by graphing. by the way the equation is all in one,not separate

Mathematics

1 answer:

victus00 [196]2 years ago

6 0

This system equation is not solution

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3 years ago

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The vertices of ABC are A(-2, 2), B(6,2), and CO, 8). The perimeter of ABC?

Alexxx [7]

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Perimeter = 22.809836694575

Step-by-step explanation:

A(-2, 2) ; B(6,2) ; C(0, 8)

$AB=\sqrt{\left( 6--2\right)^{2} +\left(2-2 \right)^{2} } =\sqrt{64} =8$

$AC=\sqrt{\left( 0--2\right)^{2} +\left(8-2 \right)^{2} } =\sqrt{40} =2\sqrt{10}$

$BC=\sqrt{\left( 0-6\right)^{2} +\left(8-2 \right)^{2} } =\sqrt{72} =6\sqrt{2}$

Then

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$=8+6\sqrt{2} +2\sqrt{10}$

= 22.809836694575

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2 years ago

3(x+4) - 5(x - 1) < 5

DaniilM [7]

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3 years ago

I have to solve this system equation by graphing. by the way the equation is all in one,not separate​

I have to solve this system equation by graphing. by the way the equation is all in one,not separate