Using derivatives, it is found that:
i) 
ii) 9 m/s.
iii) 
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:

item i:
Velocity is the <u>derivative of the position</u>, hence:

Item ii:

The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:

Item iv:

The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:




Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
The answers is A. 60 degrees
I think it would be B but I'm not sure
Step-by-step explanation:
product=× three=3 a number is unknown =x plus=+ five=5 is=equals to 20
3×x +5=20
3x+5=20
Subtract 5 from both sides
3x+5-5=20-5
3x=15
3x/3=15/3
x=5
Answer: 28-6x
This is the same as -6x+28
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To get that answer, you multiply each term inside the parenthesis by the outer term 2
14 * 2 = 28
-3x * 2 = -6x
So,
(14-3x)*2 = 14*2 - 3x*2 = 28-6x
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The distribution rule says
a(b-c) = ab-ac
which is the same as saying
(b-c)a = ba-ca
We can flip things around because we can multiply in any order.