The vertex is at (0, 3) so y=a(x-0)²+3, which is y=ax²+3
next, use a given point to find a: 10=a(3)²+3, so 9a=7, a=7/9
the equation is then y=
as for the first question, the shape is an ellipse, the domain is -5≤x≤5, the range is -3≤y≤3
the equation can be written as :
Answer:
All given information leads to conclusion described on statement. ()
Step-by-step explanation:
The strategy of problem consist in make a mathematical demonstration from given information. There are two assumptions: i) is a point of segment and ii) is the midpoint of . We proceed to perform the demonstration:
1) , is the midpoint of . Given.
2) Definition of midpoint.
3) Definition of segment/Result.
All given information leads to conclusion described on statement. ()
Answer:
120°
Step-by-step explanation:
I drew a picture that will make it easier to understand what's going on. Please see the attached image
In a rhombus, the diagonals bisect the opposite angles, and opposite angles are congruent.
Let's say angle 1 is x. The interior angles of a quadrilateral add up to 360°, so
30+30+30+30+2x=360
2x=240
x=120
angle 1 is 120°.
Answer:
First blank = 236
Second blank = 60
Third blank = 656
Step-by-step explanation:
For first blank; n = 20
f(n) = 7(20) + 96
= 236
For second blank; f(n) = 516
⇒ 516 = 7n + 96
⇒ n = 60
For third blank; n = 80
f(n) = 7(80) + 96
= 656
Answer:
nothing
Step-by-step explanation:
just because i wanted to do this