Waiting on the answer choices so i can answer your question :)
The solution would be like this for this specific problem:
sin(θ°) = √(2)/2
θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° −
sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ
360°*0 + 45° = 45°
360°*0 + 135° = 135°
360°*1 + 45° = 405°
<span>sin(225°) = -√(2)/2
</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta
cannot be 225 degrees.
The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0
Thus, the equation of the trend line, in variables K and J, is
K = 2J + 28
Answer:
Step-by-step explanation:
We have been given a function 
. We are asked to find the zeros of our given function.
To find the zeros of our given function, we will equate our given function by 0 as shown below:
Now, we will factor our equation. We can see that all terms of our equation a common factor that is 
.
Upon factoring out , we will get:
Now, we will split the middle term of our equation into parts, whose sum is 
and whose product is 
. We know such two numbers are 
.
Now, we will use zero product property to find the zeros of our given function.
Therefore, the zeros of our given function are .
40%less
You take 36/60
That equals 60%
This means that 36 is 60% of 60
So in 24 is 40% of 60 or 36 is 40% less than 60
