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3 years ago

A diver is 18 feet below sea level. After he swims up 11 feet towards the surface, what is his elevation, written as an integer?

Mathematics

1 answer:

mart [117]3 years ago

3 0

When I searched the answer up it gave me 279 or 197

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How to write a expression for: Jasmin has increased her $45 by m dollars and then spends a third of the entire amount.

siniylev [52]

The first part is addition.
45+m
If she spend a third of it, you could multiply by 1/3 or divide by 3.
Multiply: 45+m x 1/3
Divide: 45+m/3

6 0

3 years ago

Solve for x 3(x-1)-5=-3(-6x+4)-5x

Romashka [77]

Answer: x= 2/5

Step-by-step explanation:

3(x-1) - 5 = -3(-6x+4) - 5x

Remove parenthesis

3x-3-5=18x-12-5x

Calculate and combine like terms

3x-8=13x-12

Move terms

3x-13x=-12+8

add like terms

-10x=-4

divide both sides ny -10

x=2/5

5 0

3 years ago

Each car on a commuter train ca seat 114 pessengers,If the train has 7 cars,how many pessengers can the train seat

blagie [28]

It would be 1008 people because all you would do is 114 times 7 and that would be the answer. Why? Because you need to take the amount of people per train and multiply that by the amount of cars. Hope this helped comment if it did!

5 0

3 years ago

What is 1+1+1+11+1+1+0+1+11+1 x 0+1=?

pantera1 [17]

$1\times0=0\\\\1+1+1+11+1+1+0+1+11+\underbrace{1\times0}_{=0}+1=29$

5 0

4 years ago

Read 2 more answers

b. Find a 99% confidence interval for mean age of ICU patients using the facts that, in the sample, the mean is 57.55 years and

rjkz [21]

Answer:

99% of confidence intervals for mean age of ICU patients

(53.8920 , 61.2079)

Step-by-step explanation:

Explanation:-

Given sample mean $x^{-} = 57.55$

Given standard error is determined by

S.E = $\frac{S.D}{\sqrt{n} }$

Given data standard error = 1.42

99% of confidence intervals for mean is determined by

$(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.01} \frac{S.D}{\sqrt{n} } )$

$Z_{\frac{\alpha }{2} } = Z_{\frac{0.01}{2} } = Z_{0.05} = 2.576$

$(x^{-} - 2.576 S.E , x^{-} + 2.576 S.E)$

$(57.55 - 2.576X 1.42 , 57.55+ 2.576 X1.42)$

(53.8920 , 61.2079)

Conclusion:-

99% of confidence intervals for mean is determined by

(53.8920 , 61.2079)

5 0

3 years ago