Question

In the accompanying diagram, isosceles triangle ABC has coordinates A(-4,0), B(4,0), C(0,4). Find the area of ABC.

Answer 1

Answer:

The area of triangle ABC is $16\ units^{2}$

Step-by-step explanation:

we know that

The area of a triangle is equal to

$A=\frac{1}{2}(b)(h)$

In this problem we have

$b=AB=4-(-4)=8\ units$ ---> the length of the base b is the difference of the x-coordinates between A and B

$h=OC=4-0=4\ units$ ---> the height h is the difference of the y-coordinates between C and the origin O

substitute the values in the formula

$A=\frac{1}{2}(8)(4)$

$A=16\ units^{2}$