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3 years ago

help me with the Quadratic equation.... x2+ (p - 5) x + 2q = 0 has the roots −3 and 6. Find the value of P and the value of q.

Mathematics

1 answer:

nirvana33 [79]3 years ago

8 0

Step-by-step explanation:

The quadratic equation is x² + (p - 5)x + 2q = 0.

By Vieta's Formula,

we have SOR = -b/a and POR = c/a.

=> (-3) + (6) = -(p - 5) and (-3)(6) = 2q.

=> 3 = 5 - p and -18 = 2q

Hence, p = 2 and q = -9.

Alternate Method:

We have (x + 3) and (x - 6) as factors of the quadratic equation x² + (p - 5)x + 2q = 0.

=> (x + 3)(x - 6) = x² - 3x - 18.

By Comparing Coefficients,

(p - 5) = -3 and 2q = 18.

Hence p = 2 and q = -9.

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help me with the Quadratic equation.... x2+ (p - 5) x + 2q = 0 has the roots −3 and 6. Find the value of P and the value of q.​

help me with the Quadratic equation.... x2+ (p - 5) x + 2q = 0 has the roots −3 and 6. Find the value of P and the value of q.