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bulgar [2K]
2 years ago
5

My question is this can you help me​

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
4 0

Answer:

It's 1/4

Step-by-step explanation:

It's closer to 0 than the other fractions

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Given f(x)=-4+1 find f(2)
AleksAgata [21]
I think you left out something, is it -4x+1
8 0
3 years ago
The front of a storage bunker can be modeled by y=-5/216(x-72)(x+72), where x and y are measured in inches. The x axis represent
german
As far as I can make out this one.

the bunker is a 3D object, it has a height, with and length, however we're only concerned with the 2D front face, which has a length and width only.

we know the x-axis is the ground level, so the y-axis must be the scale for the length.

if we can find, using the provided model, the x-intercepts, namely where the x-axis gets touched, we can just get the distance between them and that's the ground level width.

keeping in mind that when the graph touches the x-axis, an x-intercept, "y" is 0.

\bf y=-\cfrac{5}{216}(x-72)(x+72)\implies \stackrel{y}{0}=-\cfrac{5}{216}(x-72)(x+72)
\\\\\\
0=\stackrel{\textit{difference of squares}}{(x-72)(x+72)}\implies 0=x^2-72^2\implies 72^2=x^2
\\\\\\
\pm\sqrt{72^2}=x\implies \pm 72=x

now, the distance from (-72, 0) and (72, 0) is just 72 +72, or 144.
3 0
2 years ago
Find the quotient of 2/7 and 3/5
charle [14.2K]
The quotient of 2/7 is 2 ÷ 7 = 0.285714
And 3/5 is 3 ÷ 5 = 0.6
6 0
2 years ago
Read 2 more answers
I really need help!
aleksklad [387]

Answer:

3/20

Step-by-step explanation:

Total number of students = 15 + 10 = 25

Number of girls = 10

Number of ways to select 2 students =

Number of ways to select 2 girls =

Compute the probability of selecting two girls as follows:

Thus, the probability that both students are girls is 0.15.

0.15 simplified in fraction from: 3/20

8 0
2 years ago
Find all the zeros of the function f(x) = x^3 -2x^2 +16x -32
Alex777 [14]

Answer:

<h2>Real zeros: x = 2</h2><h2>All zeros: x = 2, x = -4i and x = 4i</h2>

Step-by-step explanation:

f(x)=x^3-2x^2+16x-32\\\\\text{The zeros:}\\\\f(x)=0\Rightarrow x^3-2x^2+16x-32=0\\\\x^2(x-2)+16(x-2)=0\\\\(x-2)(x^2+16)=0\iff x-2=0\ \vee\ x^2+16=0\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}\\\\x^2+16=0\qquad\text{subtract 16 from both sides}\\x^2=-16

8 0
3 years ago
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