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kap26 [50]
3 years ago
12

In the storage room, folders are stored in packages

Mathematics
2 answers:
Bumek [7]3 years ago
5 0

Answer:

5

Step-by-step explanation:

35/8 = 4.375

You round up to 5

Brilliant_brown [7]3 years ago
3 0

Answer:

5 packages

Step-by-step explanation:

35/8 = 4.375

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A basketball gymnasium is 25 meters high, 80 meters wide and 200 meters long. We want to connect two strings, one from each of t
Rudiy27

Answer:

a) the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be 216.85 m

c) the angle that is formed by the strings is  1.23 rad

Step-by-step explanation:

assuming that we stand on one of the corners on the floor , so our coordinates are (0,0,0)  , then the coordinates of the center of the gymnasium   are found through

x center = (25 + 0)/2 = 12.5 m

y center = (80+ 0)/2 = 40 m

z center = (200+ 0)/2 = 100 m

then the centre is at (12.5 m, 40 m , 100 m ) with respect to our position

b) the length of the strings S will be the modulus of the vector that points from our position to the diagonally opposite corners

|S| = √(25²+80²+200²) = 216.85 m

c) the angle can be found through the dot product of the vectors that represent the strings S₁ and S₂

S₁ =(25,80,10)

S₂ =(-25,80,100)

then

S₁*S₂ = 25*(-25) +80*80 + 100*100 = 15775

but also

S₁*S₂ = |S₁||S₂| cos θ = |S|² * cos θ

S₁*S₂ =  |S|² * cos θ

cos θ= S₁*S₂/|S|²

θ= cos ⁻¹ ( S₁*S₂/|S|² ) = cos ⁻¹ [15775/(25²+80²+200²)] = 1.23 rad

7 0
2 years ago
Helpp please find the value of s! I will give brainlist
goldenfox [79]

We have :

s - 39⁰+ s - 9⁰ = s + 29⁰

s + s - s = 29⁰ + 9⁰ + 39⁰

s = 77⁰

Answer: 77⁰

Ok done. Thank to me :>

8 0
2 years ago
Please help with this
Karolina [17]

x = -10 that is the answer your welcome

5 0
3 years ago
Find the interquartile range (IQR) of the data in the dot plot below. ms orlando
erik [133]
Answer:
1.75
Step-by-step explanation:
Low- 81
Q1-82.5
Median- 83.5
Q3-84
High- 85
5 0
2 years ago
How do you solve this?​
Paul [167]
You need to use percentage I would help but I can’t because of I’m bad at percentages
4 0
3 years ago
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