1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kamila [148]
3 years ago
14

Please help with this

Mathematics
1 answer:
Karolina [17]3 years ago
5 0

x = -10 that is the answer your welcome

You might be interested in
Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters
Mumz [18]

The various answers to the question are:

  • To answer 90% of calls instantly, the organization needs four extension lines.
  • The average number of extension lines that will be busy is Four
  • For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

<h3>How many extension lines should be used if the company wants to handle 90% of the calls immediately?</h3>

a)

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

$$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$$

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$

Generally, the equation for is  mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

b)

The probability that a call will receive a busy signal if four extensions lines are used is,

P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$

Therefore, the average number of extension lines that will be busy is Four

c)

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

Read more about extension lines

brainly.com/question/13362603

#SPJ1

8 0
2 years ago
Help me with this math question please I'm giving away brainliests​
Lyrx [107]

Answer:the first ans  (f(x)=(1/x+2)+3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Best answer gets brainiest. On Wednesday at camp, Diana went for a hike at 5:35 A.M. The hike took 1 hour and 30 minutes. As soo
Ratling [72]

Answer:

8:00am I'm not sure, sorry if I get it wrong dude...

7 0
3 years ago
What is the square of 6​
Stells [14]

Answer:6 36 2.449

Step-by-step explanation: 36 square

4 0
3 years ago
4^(4x-1)=32 <br><br> How do I solve this problem? Do I do 4 to the fourth power first?
yKpoI14uk [10]

Answer:

\large\boxed{x=\dfrac{7}{8}}

Step-by-step explanation:

4^{(4x-1)}=32\\\\(2^2)^{4x-1}=2^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\2^{2(4x-1)}=2^5\iff2(4x-1)=5\ \ \text{use the distributive property}\ a(b+c)=ab+ac\\\\(2)(4x)+(2)(-1)=5\\\\8x-2=5\qquad\text{add 2 to both sides}\\\\8x=7\qquad\text{divide both sides by 8}\\\\x=\dfrac{7}{8}

7 0
3 years ago
Read 2 more answers
Other questions:
  • Solve for x.<br> 2x+5=3-7x
    12·1 answer
  • Jillian is mailing an 8-pound package. She doesn’t know a single conversion factor that will convert pounds to grams. Which conv
    13·2 answers
  • How to solve the equation of -5 v = 60
    5·2 answers
  • Drey makes $10 an hour plus $15 an hour for every hour of overtime. Overtime hours are any hours more than 40 hours for the week
    5·1 answer
  • Ten<br> is no more than four times the sum of twice a number and three.
    13·2 answers
  • If point T was located at 4,6 and moved 3 units to the left and 2 units down, at what coordinations will point T be located
    15·1 answer
  • I need help with #3 plzz answer asap​
    6·1 answer
  • Answer wasn't 6 I need help!!​
    14·2 answers
  • Solve the system of linear equations by elimination.<br><br> 2x+5y=16<br> 3x−5y=−1<br><br> Get (x,y)
    9·2 answers
  • What's the conversion factor used to convert inches to yards?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!