D. 14
LL = 1/2 * Hsqrt3
7sqrt3 = 1/2 * ysqrt3
24.25 = ysqrt3
24.25/sqrt3 = y
y = 14
<h2>SO. ?????????????????????</h2>
Answer- Option 2
I hope that helps
Let the distance traveled by car X be x km
<span>let the distance traveled by car Y by y km </span>
<span>their paths form a right-angled triangle. </span>
<span>Let the distance between them be D km </span>
<span>D^2 = x^2 + y^2 </span>
<span>2D dD/dt = 2x dx/dt + 2y dy/dt </span>
<span>dD/dt = (x dx/dt + y dy/dt)/D </span>
<span>at the given case: </span>
<span>x = 60, y = 80 , dx/dt = 80, dy/dt = 100 </span>
<span>D^2 = 60^2 + 80^2 = 10000 </span>
<span>D = 100 </span>
<span>dD/dt = (60(80) + 80(100))/100 </span>
<span>= 128 </span>
Well 500 mm = 50 cm so if you add both segments together you will get a 50+30=80cm segment
