Can someone please helppp me idk if this is correct
2 answers:
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For this case we have the following inequality:
x> -9
The solution set of this inequality is given by:
(-9, inf)
Therefore, all the points within the given interval must belong to the graph of the inequality.
Note: see attached image.
Answer:
(-9, inf)
See attached image.
x> -9
The solution set of this inequality is given by:
(-9, inf)
Therefore, all the points within the given interval must belong to the graph of the inequality.
Note: see attached image.
Answer:
(-9, inf)
See attached image.
Answer:
PLATO Explanation in the image below :)
Answer:
see below
Step-by-step explanation:
Every vertex moves twice as far from the center of dilation as it is in the pre-image.
Perhaps the easiest image point to find is the one at lower left. In the pre-image it is 2 units left of the center of dilation, so the image point will be 2×2 = 4 units left of the center of dilation. It will be located at (-6, -2).
Other points on the image can be found either by reference to the center of dilation, or by reference to known image points. For example, the next point clockwise is 1 left and 4 up in the pre-image, so will be 2 left and 8 up from (-6, -2) in the image. That is, the pre-image point (-5, 2) becomes image point (-8, 6). You will note that (-5, 2) is 3 left and 4 up from the center of dilation, and that (-8, 6) is 6 left and 8 up from the center of dilation (twice as far away).
