Answer:
Expected winnings for one spin = 0.1
Step-by-step explanation:
Expected Value = Sum of [(Probability of X)(Value of X)]
E(X) = Σ [P(X).X]
Two Events : X = +68 , P(X) = 1/38 and X = -2 , P(X) = 37/38
E(X) = [(68) (1/38)] + [(-2)(37/38)]
[(68)(0.03)] + [(-2)(0.97)]
= 2.04 - 1.94
= 0.1
80 would be your answer for this question
Answer:

Step-by-step explanation:
P, A, and R are collinear.
PR = 54


To solve for the numerical length of PR, let's generate an equation to find the value of x.
According to the segment addition postulate:

(substitution)
Solve for x

Combine like terms


Add 2 to both sides


Divide both sides by 7



Plug in the value of x into the equation


The answer is
3^66483360316461674016
Wdym? Can you be more specific?