5H2O contain 9 moles of oxygen atom.
Explanation:
As it is given that there are six electrons with four of them unpaired in the degenerate orbital.
As in a p-orbital there are only 3 sub-orbitals, that is, , , and . In these sub-orbitals, a maximum of 6 electrons can be accommodated.
Th next higher orbital is d-orbital which can contain a maximum of 10 electrons. There are 5 degenerate orbitals present in a d-orbital.
So, a d-orbital can easily accommodate six electrons with four of them unpaired.
Thus, we can conclude that 5 degenerate orbitals are needed to contain six electrons with four of them unpaired.
In order to emit electrons, the cesium will have to absorb photons. Each photon will knock out one electron by transferring its energy to the electron. Therefore, by the principle of energy conservation, the energy of the removed electron will be equal to the energy of the incident photon. That energy is calculated using Planck's equation:
E = hf
E = 6.63 x 10⁻³⁴ * 1 x 10¹⁵
E = 6.63 x 10⁻¹⁹ Joules
The electron will have 6.63 x 10⁻¹⁹ Joules of kinetic energy
Answer:
1.53 L.
Explanation:
Given,
Volume pf hydrogen, V₁ = 153.48 mL = 0.15348 L
Temperature, T₁ = 14°C = 273+14 = 287 K
Pressure,P₁ = 973 kPa
1 atm = 101.325 kPa
973 kPa = 9.60 atm
At STP
P₂ = 1 atm
T₂ = 25° C = 273+25 = 298 K
V₂ = ?
Now,
Hence, the volume at STP is 1.53 L.