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3 years ago

Consider the sugar below. Which term best describes this sugar? disaccharide monosaccharide polysaccharide saccharide

Chemistry

1 answer:

nekit [7.7K]3 years ago

7 0

oh wait i wrote whole paragraphs let me fix this

okay so you mean this ?

a term for disaccharides would be double sugar or boise!

monosaccharides are simple sugars soluble in water. any class of sugars like glucose.

polysaccharide is starch, cellulose, or glycogen. with molecules together. a carbohydrate.

saccharide knows as to the term structure of carbohydrates. carbohydrates are plain simple? organic compounds that are aldehyde or ketone functional group. with the general chemical formula of carbohydrates is c (H O)

n. 2. n

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Iron has many isotopes but only 4 are found in significant amounts in naturally found mixtures. The amounts by mass percent are:

AnnZ [28]

Answer:

The average mass of iron to be is 54.76 amu.

Explanation:

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

Mass of Fe-54 isotope = 53.9396 amu

Percentage abundance of Fe-54 = 5.845%

Fractional abundance of Fe-54 = 0.05845

Mass of Fe-56 isotope = 55.9349 amu

Percentage abundance of Fe-56 = 91.754 %

Fractional abundance of Fe-56= 0.91754

Mass of Fe-57 isotope = 56.9354 amu

Percentage abundance of Fe-57 = 2.119%

Fractional abundance of Fe-57 = 0.002119

Mass of Fe-58 isotope = 57.9333 amu

Percentage abundance of Fe-58 = 0.282%

Fractional abundance of Fe-58 = 0.00282

Average atomic mass of iron :

$=53.9396 amu\times 0.05845+55.9349 amu\times 0.91754 +56.9354 amu\times 0.002119 + 57.9333 amu\times 0.00282=54.76 amu$

The average mass of iron to be is 54.76 amu.

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3 years ago

What must be known to determine the nature of the salt formed from a weak acid and weak base?

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D the strength of both acid and base

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Read 2 more answers

Which of the following is the preferred degree for a seismologist?

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3 years ago

10. Hydrogen peroxide (H2O2: M = 34 g mol-1) is a powerful oxidising agent that is used in concentrated solution in rocket fuel

Lubov Fominskaja [6]

Answer:

The molality of solution=12.605 m

Explanation:

We are given that

Molar mass of Hydrogen peroxide, M=34 g/mol

Density of solution, $\rho=1.11gcm^{-3}$

30% Means mass of solute (Hydrogen peroxide)=30 g

Mass of solvent =100-30=70 g

Total mass of solution, m=100 g

Number of moles of solute= $\frac{given\;mass}{molar\;mass}$

Using the formula

Number of moles of hydrogen peroxide= $\frac{30}{34}$

Now, molality of solution

$m=\frac{number\;of\;moles\;of\;solute}{mass\;of\;solvent}\times 1000$

$m=\frac{30}{70\times 34}\times 1000$

$m=12.605 m$

Hence, the molality of solution=12.605 m

6 0

4 years ago