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balandron [24]
3 years ago
15

A batch of granola uses 2 cups of honey to make 24 servings.

Mathematics
1 answer:
Helen [10]3 years ago
7 0
3.5 cups of honey will be needed
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Tell which is greater 11/15,74%
Mekhanik [1.2K]
74% is grater hope i helped
4 0
3 years ago
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If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.
Pie
Given that f^{(n)}(0)=(n+1)!, we have for f(x) the Taylor series expansion about 0 as

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n

Replace n+1 with n, so that the series is equivalent to

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}

and notice that

\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}

Recall that for |x|, we have

\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}

which means

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}
\implies f(x)=\dfrac1{(1-x)^2}
5 0
3 years ago
Akron Cinema sells an average of 500 tickets on Mondays, with a standard deviation of 50 tickets. If a simple random sample is t
Paha777 [63]

Answer:

Step-by-step explanation:

Assuming the number of tickets sales from Mondays is normally distributed. the formula for normal distribution would be applied. It is expressed as

z = (x - u)/s

Where

x = ticket sales from monday

u = mean amount of ticket

s = standard deviation

From the information given,

u = 500 tickets

s = 50 tickets

We want to find the probability that the mean will be greater than 510. It is expressed as

P(x greater than 510) = 1 - P(x lesser than or equal to 510)

For x = 510

z = (510 - 500)/50 = 0.2

Looking at the normal distribution table, the probability corresponding to the z score is 0.9773

P(x greater than 510) = 1 - 0.9773 = 0.0227

7 0
3 years ago
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DerKrebs [107]

Answer:

5 or 5/1

Step-by-step explanation:

did the math, this is the result. Not sure if it's right, correct me if I'm wrong

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Find quadratic polynomial which best fits the function f(x)=e^x and x=0, in the sense that g(0)= f(0), and g'(0) = f'(0), and g"
Dmitriy789 [7]
Let g(x)=ax^2+bx+c. Then

\begin{cases}g(0)=c\\g'(0)=b\\g''(0)=2a\end{cases}

Meanwhile, since f(x)=e^x, you have f(0)=f'(0)=f''(0)=e^0=1.

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Note that this is just the second-order Taylor polynomial for e^x about x=0.
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