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3 years ago

12

Solve the system equation

1 answer:

den301095 [7]3 years ago

4 0

<h2>Answer:</h2>

We will use substitution to solve this system for x.

$x - 2y = 27\\y = 5x\\\\x - 2(5x) = 27\\\\x - 10x = 27\\\\-9x = 27\\\\x = -3$

Now that we know what x is, we can determine y by pluging in -3 for x in one of the original equations. I will use the first one.

$-3 - 2y = 27\\\\-2y = 30\\\\y = -15\\$

We now have our solution.

D. $(-3, -15)$

We can check our answer by pluging the solution into one of the original equations to see if both sides equal each other. I will use the first equation.

$-3 - 2(-15) = 27\\\\-3 + 30 = 27\\\\27 = 27$

Since the equation checks out, our solution is correct.

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a shopkeeper buys coffee at 4.20 per kg and sells it at 63 cents per 100 g Calculate his profit percentage

Bingel [31]

420 cents for 1000 g. So 42 cents for 100 g (i crossed multiplied). %profit=63-42/42 *100=50%

7 0

2 years ago

Please help me right away.

velikii [3]

I’m pretty sure it’s c , sorry if it’s wrong tho

4 0

2 years ago

Please help!!!!!!!!!! !!

mestny [16]

Answer:

$The ~length~ is ~9.6~ units$ ✔︎

༄❁༄❁༄❁༄❁༄

$a=8\\b=2\\c=?\\d=?\\e=5$

$Using~ Pythagorean ~theorem:$

$c^2=a^2+b^2$

$c^2=(8)^2+(2)^2$

$\sqrt{c^2} =\sqrt{68}$

$c=\sqrt{68} ~or~2\sqrt{17}$

»»---------------------►

$d^2=c^2+e^2$

$d^2=(2\sqrt{17})^2+(5)^2$

$d^2=68+25$

$\sqrt{d^2} =\sqrt{93}$

$d=\sqrt{93} ~or~9.6$

$So, your~ answer ~is ~9.6$

✧⋄⋆⋅⋆⋄✧⋄⋆⋅⋆⋄✧⋄⋆⋅⋆⋄✧⋄⋆⋅⋆⋄✧

hope it helps...

have a great day!!

3 0

3 years ago

Read 2 more answers

Rachel, a 45-year-old female, bought a $120,000, 20-year life insurance policy through her employer. Rachel is paid biweekly.

Andrew [12]

Answer: the answer is $63.14.

Step-by-step explanation:

I took the test and got it correct.

7 0

2 years ago

1. Write a quadratic function, in standard form, that fits the set of points. Solve it as a system of three equations

sasho [114]

Answer:

The equation is $y=2x^2+4x-7$

Step-by-step explanation:

Let the quadratic function be

$y=ax^2+bx+c$

The point (-4,9) must satisfy this function,

$\Rightarrow a(-4)^2+b(-4)+c=9$

$\Rightarrow 16a-4b+c=9...(1)$

The point (0,-7) must also satisfy this function,

$\Rightarrow a(0)^2+b(0)+c=-7$

$\Rightarrow c=-7...(2)$

The point (1,-1) must also satisfy this function,

$\Rightarrow a(1)^2+b(1)+c=-1$

$\Rightarrow a+b+c=-1...(3)$

We put equation 2 into equation 1 to get;

$\Rightarrow 16a-4b-7=9$

$\Rightarrow 16a-4b=16$

$\Rightarrow 4a-b=4...(5)$

We again put equation 2 into equation 3 to get;

$\Rightarrow a+b-7=-1$

$\Rightarrow a+b=6...(6)$

We add equation 5 and 6 to get;

$5a=10$

$\Rightarrow a=2$

We put $a=2$ into equation 6 to get;

$2+b=6$

$\Rightarrow b=6-2$

$\Rightarrow b=4$

The equation is therefore $y=2x^2+4x-7$

5 0

2 years ago