Answer: B 2x
1/2x-3+3/2x+3
Answer:
The answer to your question is below
Step-by-step explanation:
To solve this problem, for a and c, just look in the x-axis the value given and find the value of a and c in the y-axis.
To solve this problem, for b and d, just look in the y-axis the value given and find the value of b and d in the x-axis.
f(2) = -3 a = -3
f(b) = 0 b = -4
f(-2) = -1 c = -1
f(d) = -6 d = 8
Answer:
um... you are wrong
Step-by-step explanation:
its the the last one
you can't add when its division
you can change exponents from 1/x^-2
to x^2
<h2>
<em><u>I nweed brainliest</u></em></h2>
Check the picture below.
well, HIJK is a parallelogram only if its diagonals bisect each other, if that's so, the midpoint of HJ is the same as the midpoint of IK, let's check
![~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ H(\stackrel{x_1}{0}~,~\stackrel{y_1}{5})\qquad J(\stackrel{x_2}{4}~,~\stackrel{y_2}{-1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 4 + 0}{2}~~~ ,~~~ \cfrac{ -1 + 5}{2} \right)\implies \left( \cfrac{4}{2}~~,~~\cfrac{4}{2} \right)\implies \boxed{(2~~,~~2)} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bmiddle%20point%20of%202%20points%20%7D%20%5C%5C%5C%5C%20H%28%5Cstackrel%7Bx_1%7D%7B0%7D~%2C~%5Cstackrel%7By_1%7D%7B5%7D%29%5Cqquad%20J%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B-1%7D%29%20%5Cqquad%20%5Cleft%28%5Ccfrac%7B%20x_2%20%2B%20x_1%7D%7B2%7D~~~%20%2C~~~%20%5Ccfrac%7B%20y_2%20%2B%20y_1%7D%7B2%7D%20%5Cright%29%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28%5Ccfrac%7B%204%20%2B%200%7D%7B2%7D~~~%20%2C~~~%20%5Ccfrac%7B%20-1%20%2B%205%7D%7B2%7D%20%5Cright%29%5Cimplies%20%5Cleft%28%20%5Ccfrac%7B4%7D%7B2%7D~~%2C~~%5Ccfrac%7B4%7D%7B2%7D%20%5Cright%29%5Cimplies%20%5Cboxed%7B%282~~%2C~~2%29%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ I(\stackrel{x_1}{3}~,~\stackrel{y_1}{3})\qquad K(\stackrel{x_2}{1}~,~\stackrel{y_2}{1}) ~\hfill \left(\cfrac{ 1 + 3}{2}~~~ ,~~~ \cfrac{ 1 + 3}{2} \right)\implies \boxed{(2~~,~~2)}](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bmiddle%20point%20of%202%20points%20%7D%20%5C%5C%5C%5C%20I%28%5Cstackrel%7Bx_1%7D%7B3%7D~%2C~%5Cstackrel%7By_1%7D%7B3%7D%29%5Cqquad%20K%28%5Cstackrel%7Bx_2%7D%7B1%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%20~%5Chfill%20%5Cleft%28%5Ccfrac%7B%201%20%2B%203%7D%7B2%7D~~~%20%2C~~~%20%5Ccfrac%7B%201%20%2B%203%7D%7B2%7D%20%5Cright%29%5Cimplies%20%5Cboxed%7B%282~~%2C~~2%29%7D)