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den301095 [7]
2 years ago
8

The year of Average 11, 15, 17, X+1, 19, X-2, 3 is 14. Find median.​

Mathematics
2 answers:
malfutka [58]2 years ago
7 0

Answer:

median of given data is 18

Jlenok [28]2 years ago
3 0
The data given is 11, 15, 17, x + 1, 19, x – 2, 3 Read more on Sarthaks.com - https://www.sarthaks.com/975527/for-the-data-11-15-17-x-1-19-x-2-3-if-the-mean-is-14-find-the-value-of-x-also-find-the-mode-of-the-data
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Write the equation of the line that passes through (4,-3) &amp; (3,0)<br> m =<br> b =<br> y =
bezimeni [28]

Answer:

m = -3

b = 9

y = -3x + 9

Step-by-step explanation:

Let us solve the question

∵ The line passes through points (4, -3) and (3, 0)

∵ The rule of the slope is m = \frac{y2-y1}{x2-x1}

∵ (x1, y1) and (x2, y2) are 2 points on the line

∴ x1 = 4 and y1 = -3

∴ x2 = 3 and y2 = 0

→ Substitute them in the rule of the slope to find it

∵ m = \frac{0--3}{3-4} = \frac{0+3}{-1} = -3

∴ m = -3

∵ The form of the equation of the line is y = m x + b

→ Substitute the value of m in the form of the equation.

∴ y = -3x + b

→ To find b substitute x and y by the coordinates of the point (3, 0) or (4, -3)

∵ x = 3 and y = 0

∴ 0 = -3(3) + b

∴ 0 = -9 + b

→ Add 9 to both sides

∴ 9 = b

∴ b = 9

→ Substitute the value of b in the equation

∵ y = -3x + 9

∴ The equation of the line is y = 3x + 9

7 0
2 years ago
The triangle on the right is a scaled copy of the triangle on the left. Identify the scale factor. Express your answer in simple
Rama09 [41]

Answer:

17/9

Step-by-step explanation:

The scaled figure in the right is larger, thus the scale factor is greater than 1.

6 0
2 years ago
Read 2 more answers
X^2/4xy•x/6•3y^5/x^4
Korvikt [17]

Answer:

Simplify the expression.

X²y⁶/8x²

5 0
2 years ago
Need help with AP CAL
anzhelika [568]

Answer: Choice C

\displaystyle \frac{1}{2}\left(1 - \frac{1}{e^2}\right)

============================================================

Explanation:

The graph is shown below. The base of the 3D solid is the blue region. It spans from x = 0 to x = 1. It's also above the x axis, and below the curve y = e^{-x}

Think of the blue region as the floor of this weirdly shaped 3D room.

We're told that the cross sections are perpendicular to the x axis and each cross section is a square. The side length of each square is e^{-x} where 0 < x < 1

Let's compute the area of each general cross section.

\text{area} = (\text{side})^2\\\\\text{area} = (e^{-x})^2\\\\\text{area} = e^{-2x}\\\\

We'll be integrating infinitely many of these infinitely thin square slabs to find the volume of the 3D shape. Think of it like stacking concrete blocks together, except the blocks are side by side (instead of on top of each other). Or you can think of it like a row of square books of varying sizes. The books are very very thin.

This is what we want to compute

\displaystyle \int_{0}^{1}e^{-2x}dx\\\\

Apply a u-substitution

u = -2x

du/dx = -2

du = -2dx

dx = du/(-2)

dx = -0.5du

Also, don't forget to change the limits of integration

  • If x = 0, then u = -2x = -2(0) = 0
  • If x = 1, then u = -2x = -2(1) = -2

This means,

\displaystyle \int_{0}^{1}e^{-2x}dx = \int_{0}^{-2}e^{u}(-0.5du) = 0.5\int_{-2}^{0}e^{u}du\\\\\\

I used the rule that \displaystyle \int_{a}^{b}f(x)dx = -\int_{b}^{a}f(x)dx which says swapping the limits of integration will have us swap the sign out front.

--------

Furthermore,

\displaystyle 0.5\int_{-2}^{0}e^{u}du = \frac{1}{2}\left[e^u+C\right]_{-2}^{0}\\\\\\= \frac{1}{2}\left[(e^0+C)-(e^{-2}+C)\right]\\\\\\= \frac{1}{2}\left[1 - \frac{1}{e^2}\right]

In short,

\displaystyle \int_{0}^{1}e^{-2x}dx = \frac{1}{2}\left[1 - \frac{1}{e^2}\right]

This points us to choice C as the final answer.

5 0
1 year ago
Tai’s baby brother weighs 3,745 grams. What is his weight in kilograms?
Rus_ich [418]

Answer:

3.745 kg

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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