f(x)=lnx
y=f(x)
dy/dx= 1/x
tangent at (x,y) has slope 1/x
eqn of tangent is y = mx + c
since the tangent passes through origin, c=0
substitute y = lnx and m= 1/x to above eqn
lnx = 1
x=e
y=lne=1
Area of a circle = pi r^2 = pi * 12^2 = 452.4 in^2 to nearest tenth.
Negative, You'll have to explain the why part though,
Answer:

Step-by-step explanation:
Remember that the range is the set of all y-values. Thus, since the minimum of the function is y=-1, then our range is
. In interval notation, we use brackets to show what's included and parentheses to show what's not included.
Answer:
answer 45
Step-by-step explanation:
it is thr right answe