<span>a) Intervals of increase is where the derivative is positive
b) </span> <span>Intervals of decrease is where the derivative is negative. </span> 
c) <span>Inflection points of the function are where the graph changes concavity that is the point where the second derivative is zero </span>
<span>d) 
Concave up- Second derivative positive </span>
<span>Concave down- second derivative negative </span>
f(x) = 4x^4 − 32x^3 + 89x^2 − 95x + 31 
<span>f '(x) = 16x^3 - 96x^2 + 178x - 95 </span>
<span>f "(x) = 48x^2 - 192x + 178 </span>
<span>By rational root theorem the f '(x) has one rational root and factors to: </span>
<span>f '(x) = (2x - 5)*(8x^2 - 28x + 19) </span>
<span>Using the quadratic formula to find it's two irrational real roots. </span>
<span>The f "(x) = 48x^2 - 192x + 178 only has irrational real roots, use quadratic formula which will be the inflection points as well.</span>
        
                    
             
        
        
        
Intersect
Meet/Touch/Cross
Perpendicular or Transversals
Meet/Touch/Cross
Correct me if I'm wrong.
 
        
             
        
        
        
Y =-6/5x+7/5 Please vote me as brainliest if you think i helped and i attached a photo with work as well :) Have a great day
 
        
        
        
Answer:
A) h(x)=9x-13 
Step-by-step explanation:
f(x) = 2x - 1  
g(x) = 7x -12 
Add them together
f(x) = 2x - 1  
g(x) = 7x -12 
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f(x)+g(x) = 9x-13
h(x) = 9x-13
 
        
                    
             
        
        
        
Answer: the answer is 8 because
Step-by-step explanation: