The key idea is that, if a vector field is conservative, then it has curl 0. Equivalently, if the curl is not 0, then the field is not conservative. But if we find that the curl is 0, that on its own doesn't mean the field is conservative.
1.

We want to find
such that
. This means



so
is conservative.
2.

Then




so
is conservative.
3.

so
is not conservative.
4.

Then




so
is conservative.
Answer:
A
Step-by-step explanation:
sin A=(opposite side)/hypotenuse=a/c
cos A=(adjacent side)/hypotenuse=b/c
tan A=(opposite side)/(adjacent side)=a/b
Answer:
-5x + 0y = -11
The y terms are eliminated
Step-by-step explanation:
- 4x – 2y = -2
X - 2y = 9
We want to subtract the second equation from the first
Distribute a minus sign to all the terms in the second equation
- 4x – 2y = -2
X - 2y = 9
= (-5x + 0y = -11)
Answer:
the answer is the second to the left :D
Step-by-step explanation:
each number is divided then you solve\
The answer would be B and here’s the steps :)