What is the line segments between (4,-6) and (-6,-16)?

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

5 0

4 years ago

The authors of a paper concluded that more boys than girls listen to music at high volumes. This conclusion was based on data fr

schepotkina [342]

Answer:

Since the calculated value of z= 2.82 does not lie in the critical region the null hypothesis is accepted and it is concluded that the sample data support the authors' conclusion that the proportion of the country's boys who listen to music at high volume is greater than this proportion for the country's girls.

The value of p is 0 .00233. The result is significant at p < 0.10.

Step-by-step explanation:

1) Let the null and alternate hypothesis be

H0: μboys − μgirls > 0

against the claim

Ha: μboys − μgirls ≤ 0

2) The significance level is set at 0.01

3) The critical region is z ≤ ± 1.28

4) The test statistic

Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]

Here p1= 397/768= 0.5169 and p2= 331/745=0.4429

pc = 397+331/768+745

pc= 0.4811

qc= 1-pc= 1-0.4811=0.5188

5) Calculations

Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]

z= 0.5169-0.4429/√ 0.4811*0.5188( 1/768+ 1/745)

z= 2.82

6) Conclusion

Since the calculated value of z= 2.82 does not lie in the critical region the null hypothesis is accepted and it is concluded that the sample data support the authors' conclusion that the proportion of the country's boys who listen to music at high volume is greater than this proportion for the country's girls.

7)

The value of p is 0 .00233. The result is significant at p < 0.10.

8 0

3 years ago

If Roberto does a job in 11 hours and with the help of Sarah they can do it together in 2 hours, how long would it take Sarah to

Levart [38]

I think it is seven but im probaly wrong

3 0

4 years ago

How to subtract a negative fraction from a positive fraction?

ikadub [295]

Let's take an example to illustrate this case:

positive fraction = 2/7

negative fraction = - 3/5

Now we need to subtract - 3/5 from 2/7

Right?

2/7 - (-3/5) = 2/7 + 3/5

here we need to unify the denominators as follows:

the lowest common factor between 7 and 5 is 35
2/7 = 10/35
3/5 = 21/35

Now back to 2/7 + 3/5:

2/7 + 3/5 = 10/35 + 21/35 = (10+21)/35 = 31/35

That's it

Hope that helps you

8 0

3 years ago

F =(11,5) Find: 7f.

lys-0071 [83]

Answer:

$f = (115) \\ 7f = 7 \times f(115) = 805$

6 0

3 years ago