Answer:
Step-by-step explanation:
a)

this can be done by substitute lnx = u
dx/x = du
When x =1, u =0 and when x =2, u = ln 2
So integral = 
We find that this integral value is not definid for p =1
Hence for values of p other than 1, this converges.
When we substitute limits

and converges for p ≠1
b) 
So not converging for p =1
But ln x is defined only for x >0
So integral 0 to 1 makes this integral not valid and hence not convergent.
We are given
x1 = 10 ft
y1 = 14 ft
x2 = 13 ft
y2 = 9 ft
We are asked to find the distance between the base of the house to the closest treetop.
So,
d1 = √(10² + 14²) = 17.20
d2 √(13² + 9²) = 15.81
The distance is 15.81 ft to the closest treetop which is the tree 13 feet from the base of the house.
Answer:
[1 , +∞)
Step-by-step explanation:

Answer:
20.875
Step-by-step explanation: