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djyliett [7]
3 years ago
13

I dont know what the answer to this problem is i need help

Mathematics
2 answers:
marishachu [46]3 years ago
8 0

Answer:

The answer to your question is choice a

rewona [7]3 years ago
4 0
Cone A will certainly hold more. Just don’t know the exact amount
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The diagram shows several planes, lines, and points. Vertical plane P intersects horizontal plane R at line f. Vertical plane T
Rudiy27

Please mark brainliest

Answer:

Line H has points on planes R, T, P

Step-by-step explanation:

I just took the test on Edgenuity 2020. Good luck

5 0
3 years ago
Help Fast Show WORK and. NO links <br> 5f = -75 check your solutio\
pantera1 [17]

Answer:

f= -15

Step-by-step explanation:

u just have to divide

-75/5= -15  so f equal -15

3 0
3 years ago
Read 2 more answers
Tia measured a greeting card and found that it was 1 decimeter long. How many centimeters are in 1 decimeter?
Advocard [28]

Answer:

10 cm

Step-by-step explanation:

1 decimeter is equal to 10⁻¹ meters.

1 meter is equal to 10² centimeters. We can use a conversion fraction to find the centimeters corresponding to 10⁻¹ meters.

10⁻¹ m × (10²cm/1 m) = 10 cm

1 dm = 10⁻¹ m

10⁻¹ m = 10 cm

Due to the transitive property, 1 decimeter is equal to 10 centimeters.

4 0
3 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
2 years ago
Quadrilateral abcd is a rhombus and points c, d, and e are on the same line. is quadrilateral abde a rhombus?
Step2247 [10]
No, because BC and BD are not the same lengths. If AB = BC, then AB and BD are not the same lengths -> ABDE is not a rhombus.
6 0
3 years ago
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