May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Answer:
m∠1 + m∠3
Step-by-step explanation:
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Answer: (a)
Step-by-step explanation:
Suppose the original function is 
To shift it 2 units right, replace x by x-2 such that
So, the function becomes 
Answer:
the answer would be 20
Step-by-step explanation:
so if 18-(-2)=?
two nwgatives make a positive. So the equation would turn into 18+2=20
Im not 100% if this is right but htis is how I was taught to do it.
Answer:
Step-by-step explanation:I belive that the 7x+22 needs to equal 50 because they opposite angles. Hope this helped a little and can get you started
