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frutty [35]
3 years ago
6

Please help Help !!!!!!!

Mathematics
2 answers:
Vilka [71]3 years ago
6 0
I think the correct answer to the question is 9
lesantik [10]3 years ago
3 0
B. 9, we know that this triangle is a 30-60-90 and that c/hypotenuse=2a and b=a√3 so since you know that a=3√3 you can do 3√3 ² which would give you 9 for the hypotenuse
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Please help I will give Brainliest
omeli [17]

Answer:

The odd function is written f (x) = (x) and rounds the odd numbers to the nearest integer.

The graph of f (x) = (x) includes the point (17/4), (7/2), (15/6)

Step-by-step explanation:

The odd function seeks to round odd numbers, with fractions of first odd numbers and then even by adding 3 to them.

5 0
2 years ago
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A salesperson's daily earnings include $115 per day plus commission equal to x percent (in decimal form) of his daily sales.
bearhunter [10]

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it might be 8%

Step-by-step explanation:

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3 years ago
Find the measure of Angle Q.
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Answer:

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2 years ago
Simplify -2.9f + .9f -12 - 4
Natalka [10]

\huge\text{Hey there!}

\large\text{-2.9f + 0.9f -12 - 4}\\\\\large\text{COMBINE the LIKE TERMS}\\\\\large\text{(-2.9f + 0.9f) + (-12 - 4)}\\\\\large\text{(-2.9f + 0.9f) = \bf{-2f}}\\\\\large\text{(-12 - 4) = \bf{-16}}\\\\\large\text{= \bf{-2f - 16}}\\\\\\\boxed{\boxed{\large\text{Answer: \bf{-2f - 16}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

6 0
3 years ago
Find the unit tangent vector T(t) to the curve r(t) = [sin(t), 1 + t, cos(t)] when t = 0.
ss7ja [257]

Compute the derivative of \mathbf r(t) at t=0 - this will be the tangent vector - then normalize it by dividing it by its magnitude to get the unit tangent vector \mathbf T(t).

\mathbf r(t) = \langle \sin(t), 1+t, \cos(t) \rangle \implies \dfrac{d\mathbf r}{dt} = \langle \cos(t), 1, -\sin(t) \rangle \implies \dfrac{d\mathbf r}{dt}(0) = \langle 1, 1, 0 \rangle

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\implies\mathbf T(0) = \dfrac{\langle1,1,0\rangle}{\sqrt2} = \boxed{\left\langle \dfrac1{\sqrt2}, \dfrac1{\sqrt2}, 0\right\rangle}

7 0
2 years ago
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