3/2? I’m not much of a math person so I don’t know for sure !!
Answer:
(7a^2 + 8b^2 + 5ab) (7a^2 + 8b^2 - 5ab)
Step-by-step explanation:
Dado que ambos términos son cuadrados perfectos, puede factorizar utilizando la fórmula de la diferencia de cuadrados, a^2 - b^ 2 = (a + b) (a - b), donde a = 7a^2 + 8b^2 y b = 5ab.
English: Since both terms are perfect squares you can factor using the difference of squares formula, a^2 - b^2 = (a + b)(a - b), where a = 7a^2 + 8b^2 and b = 5ab.
False. When a quadrilateral has two sets of parallel sides ,like I drew below, all four corners form right angles.
Answer:Number Sets. There are sets of numbers that are used so often they have special names and symbols: ... The numbers you can make by dividing one integer by another (but not dividing by zero). In other words ... If you square a real number you always get a positive, or zero, result. ... x + 7 = 0, x = −7, Integers, set integer.
Step-by-step explanation:
![\sqrt[4]{ \frac{24x^{6}y}{128x^{4}y^{5}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%20%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D)
![\sqrt[4]{ \frac{3x^{2}}{16y^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%20%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D)
![\frac{ \sqrt[4]{3x^{2}}}{2y}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%5B4%5D%7B3x%5E%7B2%7D%7D%7D%7B2y%7D%20)
