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satela [25.4K]
3 years ago
10

Someone chat w me thru the comments on this question. im grounded and lonely. love you hehe

Mathematics
2 answers:
julsineya [31]3 years ago
6 0

Answer:

r

Step-by-step explanation:

nikitadnepr [17]3 years ago
3 0

Answer:

point yktv

Step-by-step explanation:

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This then makes your answer
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Read 2 more answers
the participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men an
Nostrana [21]

Answer:

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = \frac{56}{1024} = 0.0546

Step-by-step explanation:

The participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men and women

That is probability of participants of television quiz of equal numbers of men and women that is 50 %of men and 50% of women.

p = 50/100 = 1/2

q = 1-p = 1 - 1/2 = 1/2

n =10

we will use binomial distribution p(x =r) = n_{cr} p^{r} q^{n-r}

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = P(x=0)+P(x=1)+P(x=2)

          = 10_{c0} \frac{1}{2} ^{0} (\frac{1}{2}) ^{10-0}+ 10_{c1} \frac{1}{2} ^{1} (\frac{1}{2}) ^{10-1   \\   + 10_{c2} \frac{1}{2} ^{2} (\frac{1}{2}) ^{10-2

          by using formula n_{cr} =\frac{n!}{(n-r)!r!}

on simplification we get

     = 10_{c0}  (\frac{1}{2}) ^{10}+ 10_{c1} (\frac{1}{2}) ^{10) + 10_{c2} (\frac{1}{2}) ^{10)

    = 1  (\frac{1}{2}) ^{10}+ 10(\frac{1}{2}) ^{10)+45  (\frac{1}{2}) ^{10}

  = \frac{56}{1024} = 0.0546

<u>Conclusion</u>:-

The probability of getting 2 or fewer women when 10 people are picked

P(x≤ 2) = \frac{56}{1024} = 0.0546

8 0
3 years ago
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