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Leokris [45]
2 years ago
11

Pyramid A is a square pyramid with a base side length of 7 inches and a height of 6 inches. Pyramid B has a volume of 3,136 in3.

How many times bigger is the volume of pyramid B than pyramid A? (5 points)
a. 15
b. 32
c. 54
d .75
Mathematics
1 answer:
julia-pushkina [17]2 years ago
8 0
The answer is B.
V=(7) (7) (6) / 3
V=98 in 3
3136/98=32
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2. Find the number of cubical
lys-0071 [83]

Answer:number of boxes = 60

Volume of box = side × side × side.

 = 3 × 3 × 3

= 27 cu. cm.

Volume of carton = length × breadth × height.

= 15 × 9 × 12

= 1620 cu. cm.

Number of boxes = Volume of carton/Volume of each box.

= 1620/27

= 60

Therefore, number of boxes = 60.

Step-by-step explanation:Volume of box = side × side × side.

 = 3 × 3 × 3

= 27 cu. cm.

Volume of carton = length × breadth × height.

= 15 × 9 × 12

= 1620 cu. cm.

Number of boxes = Volume of carton/Volume of each box.

= 1620/27

= 60

Therefore, number of boxes = 60.

3 0
3 years ago
Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $24 monthly fee
JulsSmile [24]

Answer:

600 minutes

Step-by-step explanation:

If we write both situations as an equation, we get:

y1 = 24 + 0.15x

<em>y1 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>paid </em><em>in </em><em>first </em><em>plan</em>

<em>x </em><em>:</em><em> </em><em>total minutes </em><em>of </em><em>calls</em>

y2 = 0.19x

<em>y2 </em><em>:</em><em> </em><em>total </em><em>cost </em><em>in </em><em>second </em><em>plan</em>

<em>x:</em><em> </em><em>total </em><em>min</em><em>utes </em><em>of </em><em>call</em>

We are now looking for the situation where the total cost in the two plans is equal, so

y1 = y2

this gives

24 + 0.15x = 0.19x

<=> 0.04x = 24

<=> x = 600

7 0
3 years ago
A child has 4 wooden blocks. How many different ways can she stack 3 of them into a tower?
faltersainse [42]

Answer:

Step-by-step explanation:

To find the number of different ways she can stack 3 of them in a tower, we need to use the formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

n = 4

k = 3

_{n}P_{k}=\dfrac{4!}{(4-3)!}

_{n}P_{k}=\dfrac{4!}{1!}

_{n}P_{k}=\dfrac{4*3*2*1!}{(1)!}

_{n}P_{k}=\dfrac{4*3*2*1!}{1}

_{n}P_{k}=\dfrac{24}{1}

7 0
3 years ago
Find the sum 51/3+(22/3+11/3)
geniusboy [140]
I think the answer is 84/3
8 0
3 years ago
Read 2 more answers
Two opposing opinions were shown to a random sample of 1,500 buyers of a particular political news app in the United States. The
kifflom [539]

Answer:

A) 98% Confidence interval for the proportion of all US buyers of this particular app who would have chosen Opinion B

= (0.51, 0.57)

This means that the true proportion of all thay would chose opinion B can take on values between the range of (0.51, 0.57)

B) For the confidence interval obtained to be valid, the conditions stated must be satisfied and for the sampling distribution to be approximately normal, the number of buyers that chose Opinion B and the number of buyers that did not choose Opinion B must both be greater than 10.

Step-by-step explanation:

Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion of all US buyers of this particular app who would have chosen Opinion B = 0.54

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value at 98% confidence interval for sample size of 1500 is obtained from the z-tables.

Critical value = 2.33

Standard error = σₓ = √[p(1-p)/n]

p = sample proportion = 0.54

n = sample size = 1500

σₓ = √(0.54×0.46/1500) = 0.0128685664 = 0.01287

98% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.54 ± (2.33 × 0.01287)

CI = 0.54 ± 0.02998)

98% CI = (0.51, 0.57)

98% Confidence interval = (0.51, 0.57)

B) The number of buyers that chose Opinion B and the number of buyers that did not choose Opinion B are both greater than 10. Why must this inference condition be met?

For this confidence interval to be obtained using sample data, a couple of conditions are necessary to be satisfied. They include;

- The sample data must have been obtained using a random sampling technique.

- The sampling distribution must be normal or approximately normal.

- The variables of the sample data must be independent of each other.

On the second point, the condition for a binomial distribution to approximate a normal distribution is that

np ≥ 10

and n(1-p) ≥ 10

The quantity np is the actual sample mean which is the actual number of buyers that chose Opinion B while n(1-p) is the number of buyers that did not chose Opinion B.

For the confidence interval obtained to be valid, the conditions stated must be satisfied and for the sampling distribution to be approximately normal, the number of buyers that chose Opinion B and the number of buyers that did not choose Opinion B must both be greater than 10.

Hope this Helps!!!

8 0
3 years ago
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