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grin007 [14]
3 years ago
10

In August 2003, 56% of employed adults in the United States reported that basic mathematical skills were critical or very import

ant to their job. The supervisor of the job placement office at a 4-year college thinks this percentage has increased due to increased use of technology in the workplace. He takes a random sample of 30 employed adults and finds that 21 of them feel that basic mathematical skills are critical or very important to their job.
Required:
Is there sufficient evidence to conclude that the percentage of employed adults who feel basic mathematical skills are critical or very important to their job has increased at the a = 0.05 level of significance?
Mathematics
1 answer:
Serga [27]3 years ago
7 0

Answer:

Yes

Step-by-step explanation:

First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.

It has mean μ= np =  30×0.56=16.8

standard deviation s = √npq

sqrt(30×0.56×(1-0.56)) = 2.71

So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.

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Answer:

The fraction is \frac{9}{15}

Step-by-step explanation:

\frac{36}{60} = \frac{x}{y}

Where x and y are the numerator and denominator of our new fraction respectively.

Also given is that x + y = 24

So  \frac{x}{y} = 36 ÷ 60 = 0.6

x = 0.6y

Substituting x in x + y = 24 gives;

0.6y + y = 24 , 1.6y = 24

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x = 24 - 15 = 9

So our fraction is \frac{9}{15}

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