y = tan^−1(x2/4) tan(y) = x2/4 sec2(y) = x/2 y′ = xcos^2(y)/2 cos^2(y) = 16x2+16 y′ = 8x/(x2+16)

let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (x2 + 16)

y at x =0 = 4 ln (16) = 11.09

6 0

3 years ago

Since f is parallel to line g, use the diagram to the right right to answer the following question (I need help with problem D a

Snezhnost [94]

Given,

The line f and g are parallel lines.

a)The measure of angle 2 is 117 degree.

By exterior atlernate angle property,

$\begin{gathered} \angle2=\angle7 \\ \angle7=117^{\circ} \end{gathered}$

The measure of angle 7 is 117 degree.

b)The measure of angle 4 is 68 degree.

By sum of adjacent angle between two parallel lines property,

$\begin{gathered} \angle4+\angle6=180^{\circ} \\ \angle6=180^{\circ}-68^{\circ} \\ \angle6=112^{\circ} \end{gathered}$

The measure of angle 6 is 112 degree.

c)The measure of angle 5 is 32 degree.

By alternate interior angle property,

$\begin{gathered} \angle4=\angle5^{} \\ \angle4=32^{\circ} \end{gathered}$

The measure of angle 4 is 32 degree.

d)The measure of angle 7 is 121 degree.

By corresponding angle property,

$\begin{gathered} \angle7=\angle3^{} \\ \angle3=121^{\circ} \end{gathered}$

The measure of angle 3 is 121 degree.

3 0

1 year ago

4. Tom bought 333 pounds of

Lady_Fox [76]

Tom bought 768 pounds of candy because 333 + 435 = 768

8 0

3 years ago