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lora16 [44]
3 years ago
15

I NEED HELP BADLYYYYYYYY PLEASE HELPPPPPPPPPPPPPPPPPPPPp

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0

Answer:

x=4

Step-by-step explanation:

I have to help a fellow turtle lover

explain x in terms of y

-5+2y=x

now replace

4(-5+2y)+y=16

9y-20=16

9y=36

x=4

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4 0
3 years ago
☝︎image<br> HELP ME PLEASEE
spin [16.1K]

Answer:

7. 5

8. 33. 3333 or 100/ 3

9. 18/7

10. 30 /7

5 0
2 years ago
Julia rounded to the nearest ten to estimate the difference between two numbers. The estimated difference was 10. What are four
serious [3.7K]

To round off to 10, the difference should range from 5 to 14. If the difference between two numbers is from 5 to 14, they all are rounded to 10.

Example:

18-9=9 (near to 10)

26-15=11

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3 0
3 years ago
What is the quotient when 4x3 + 2x + 7 is divided by x + 3?
Arte-miy333 [17]

Answer:

The quotient of this division is (4x^2 -12x + 38). The remainder here would be -26.

Step-by-step explanation:

The numerator 4x^3 + 2x + 7 is a polynomial about x with degree 3.

The divisor x + 3 is a polynomial, also about x, but with degree 1.

By the division algorithm, the quotient should be of degree 3 - 1 = 2, while the remainder shall be of degree 1 - 1 = 0 (i.e., the remainder would be a constant.) Let the quotient be a\,x^2 + b\, x + c with coefficients a, b, and c.

4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3).

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is 4 x^3. On the right-hand side, that would be a\, x^3. Hence a = 4.

Now, given that a = 4, rewrite the right-hand side:

\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}.

Hence:

4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)

Subtract \left(4x^3 + 12x^2\right from both sides of the equation:

-12x^2 + 2x + 7 = (b\,x + c)(x + 3).

The term with a degree of two on the left-hand side has coefficient (-12). Since the only term on the right hand side with degree two would have coefficient b, b = -12.

Again, rewrite the right-hand side:

\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}.

Subtract -12x^2 -36x from both sides of the equation:

38x + 7 = c(x + 3).

By the same logic, c = 38.

Hence the quotient would be (4x^2 - 12x + 38).

6 0
3 years ago
HELPP my work is due soon plus i don’t understand :(
Mashcka [7]

Answer:

4. B

5.

Step-by-step explanation:

8 0
3 years ago
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