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3 years ago

NEED SMART STUDENT?#TRIG

Mathematics

1 answer:

horsena [70]3 years ago

3 0

Tan(angle) = Opposite Leg / adjacent leg

tan(37) = x / 10

x = 10 *tan(37)

x = 7.5

You might be interested in

What is the value of the expression 9 x 4 - (2 x 1/2)

love history [14]

Answer:

35x

Step-by-step explanation:

Start with parentheses, 2 x 1/2 = 1

9 x 4 = 36

36 - 1 = 35

4 0

3 years ago

What is the slope of the line that goes through (-5,5) and (5,-7)

sladkih [1.3K]

Answer:

-1/5

Step-by-step explanation:

slope formula:

m = y₂ - y₁ / x₂ - x₁

Two points are given:

(-5, -5) (5, -7)

m = -7 - (-5) / 5 - (-5)

m = -2 / 10

m = -1/5

7 0

3 years ago

Read 2 more answers

genetic experiment with peas resulted in one sample of offspring that consisted of green peas and yellow peas. a. Construct a %

Andreas93 [3]

Complete Question

A genetic experiment with peas resulted in one sample of offspring that consisted of 432 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?

Answer:

The 95% confidence interval is $0.2392 < p < 0.3108$

No, the confidence interval includes 0.25, so the true percentage could easily equal 25%

Step-by-step explanation:

From the question we are told that

The total sample size is $n = 432 + 164 =596$

The number of offspring that is yellow peas is $y = 432$

The number of offspring that is green peas is $g = 164$

The sample proportion for offspring that are yellow peas is mathematically evaluated as

$\r p = \frac{ 164 }{596}$

$\r p = 0.275$

Given the the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100 - 95)\%$

$\alpha = 5\% = 0.0 5$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1- \r p )}{n} }$

=> $E = 1.96 * \sqrt{\frac{0.275 (1- 0.275 )}{596} }$

=> $E = 0.0358$

The 95% confidence interval is mathematically represented as

$\r p - E < p < \r p + E$

=> $0.275 - 0.0358 < p < 0.275 + 0.0358$

=> $0.2392 < p < 0.3108$

6 0

3 years ago

PLZ help thnx

Pepsi [2]

Answer:

A) $40

B) 40M = P

C) $3,120

Step-by-step explanation:

Given that at her salon, last week Tammy did 25 manicures and collected $ 1000, to calculate the slope to represent the manicures, write an equation to represent this relation and determine how much would Tammy make if she did 78 manicures in a month the following calculations should be performed:

1000/25 = X

40 = X

Thus, each manicure costs $ 40.

40M = P

78 x 40 = X

3.120 = X

So if she did 78 manicures in a month, Tammy would earn $ 3,120.

8 0

2 years ago

Kristen can lift 133% of what Jane can lift. How many times more is that?

lubasha [3.4K]

The weight Kristen can lift is 1.3 times more than Jane's

<h3>How to determine the number of times?</h3>

The given paramater can be represented using the following equation

Kristen = 133% * Jane

Express the percentage as decimal

Kristen = 1.33 * Jane

Hence, the weight Kristen can lift is 1.3 times more than Jane's

NEED SMART STUDENT?#TRIG​

NEED SMART STUDENT?#TRIG