Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Answer:
i need an answer too
Step-by-step explanation:
Answer:
9a = 11a - 2a
9a = 9a
Step-by-step explanation:
9a = 11a - 2a
11 - 2 = 9
Similarly, 11a - 2a = 9a
Eleven minus two equals nine. Similarly, 11a minus 2a equals 9a. You can subtract them because they both have the same variable <u><em>a</em></u>.
P = 4s
P = 4(28)
P = 112 ft
The perimeter of the garden is 112 feet.
