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Harrizon [31]
3 years ago
14

Match the cube roots and square roots with their values.

Mathematics
1 answer:
stiks02 [169]3 years ago
4 0

Answer:

See the attachment

Step-by-step explanation:

If you don't have these memorized yet, your calculator can help you with this.

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Need help with this question 15 (1 1/5)
lana [24]
15\left(1\dfrac{1}{5}\right)=15\cdot\dfrac{1\cdot5+1}{5}=15\cdot\dfrac{6}{5}\\\\=3\cdot6=\boxed{18}
6 0
3 years ago
The exponential function f(x) = 3(5)x grows by a factor of 25 between x = 1 and x = 3. What factor does it grow by between x = 5
Delvig [45]

Answer:

B) 25

Step-by-step explanation:

Given exponential function:

f(x)=3(5)^x

The growth factor between x=1 and x=3 is 25.

To find the growth factor between x=5 and x=7

Solution:

The growth factor of an exponential function in the interval x=a and x=b is given by :

G=\frac{f(b)}{f(a)}

We can check this by plugging in the given points.

The growth factor between x=1 and x=3 would be calculated as:

G=\frac{f(3)}{f(1)}

f(3)=3(5)^3

f(1)=3(5)^1

Plugging in values.

G=\frac{3(5)^3}{3(5)^1}

G=\frac{(5)^3}{(5)^1} (On canceling the common terms)

G=(5)^{(3-1)}  (Using quotient property of exponents \frac{a^b}{a^c}=a^{(b-c)} )

G=(5)^{2}

∴ G=25  

Similarly the growth factor between x=5 and x=7 would be:

G=\frac{f(7)}{f(5)}

f(7)=3(5)^7

f(5)=3(5)^5

Plugging in values.

G=\frac{3(5)^7}{3(5)^5}

G=\frac{(5)^7}{(5)^5} (On canceling the common terms)

G=(5)^{(7-5)}  (Using quotient property of exponents \frac{a^b}{a^c}=a^{(b-c)} )

G=(5)^{2}

∴ G=25  

Thus, the growth factor remains the same which is  =25.

3 0
3 years ago
Read 2 more answers
Instructions: Find the value of the trigonometric ratio. Make sure to simplify the fraction if needed.
harina [27]

Check the picture below.

4 0
2 years ago
ASAPPP!!!! HELP I WILL GIVE 100POINTS AND BRAINLIST Question 9 (Essay Worth 10 points)
Luda [366]

Answer:

Part A)

The <em>x-</em>intercepts are (-1/4, 0) and (4, 0).

Part B)

The vertex is a maximum because the leading coefficient is negative.

The vertex is (1.875, 72.25).

Part C)

We can plot the zeros and the vertex, and connect them with a curve.

Step-by-step explanation:

The function given is:

f(x)=-16x^2+60x+16

Part A)

To find the <em>x-</em>intercepts of the function, set the function equal to 0 and solve for <em>x: </em>

<em />0=-16x^2+60x+16<em />

We can divide both sides by negative four:

0=4x^2-15x-4

Factor:

0=(4x+1)(x-4)

Zero Product Property:

x-4=0\text{ or } 4x+1=0

Solve for each case:

\displaystyle x=-\frac{1}{4}\text{ or }x=4

Hence, our zeros are:

\displaystyle \left(-\frac{1}{4}, 0\right)\text{ and } \left(4, 0\right)

Part B)

Note that the leading coefficient of our function is negative.

So, our function will be concave down.

Hence, our vertex will be the maximum.

The vertex is given by:

\displaystyle \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)

In this case, <em>a </em>= -16, <em>b</em> = 60, and <em>c</em> = 16.

Find the <em>x-</em>coordinate of the vertex:

\displaystyle x=-\frac{(60)}{2(-16)}=\frac{15}{8}=1.875

Substitute this back into the function to find the <em>y-</em>coordinate:

f(1.875)=-16(1.875)^2+60(1.875)+16=72.25

Hence, our vertex is:

(1.875, 72.25)

Part C)

Since we already determined the zeros and the vertex, we can plot the two zeros and the vertex and draw a curve between the three points.

The graph is shown below. Again, to do this by hand, simply plot the three points and connect them with a parabola. If necessary, we can also find the <em>y-</em>intercept.

7 0
3 years ago
Urgent what is the numerical answer please !!
andrezito [222]

whats the full question?

5 0
3 years ago
Read 2 more answers
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