Answer:56
Step-by-step explanation:
We already have the lengths of the given sides:
5+7=12
12+5=17
17+5=22
22+11=33
33+7=40
40+(5+11)=56
A single die is rolled twice. the set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
Maksim231197 [3]
<span>We need to find the rolls whose sum is greater than 10. By looking at the outcomes, we see that (5,6), (6,5), and (6,6) all have a sum greater than 10. Therefore, there are 3 chances to get a sum greater than 10. Since there are 36 chances overall, the probability of rolling greater than 10 are 3/36 = 1/12.</span>
The answer is 1680. To get this you do 8*7*6*5 because there are 8 options for the first character, and then you can repeat that for the second one with 7, 6, and 5
Answer:
There will be 9 couples, and 3 lonely girls
Hope this helps
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Answer:
21
Step-by-step explanation:
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