Find the sum of the geometric series 1 - 4/5 + (4/5)² - (4/5)³ + ... - (4/5)²⁹
1 answer:
Answer:
Step-by-step explanation:
Given,
1st term (a) = 1
Common ratio (r) = -4/5
last term (l) = - 
Now,
Sum (S) = (lr- a)/(r - 1) =[(4/5)³° - 1]/(-9/5)
= -0.99876206/-1.8
= 0.5548678111
Sorry bro couldn't get answer in fraction.
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Step-by-step explanation:
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Step-by-step explanation:
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