You should know that:
(a+b)(a+b)(a+b)
=a(a+b)(a+b)+b(a+b)(a+b)
=a(a²+2ab+b²)+b(a²+2ab+b²)
=a³+2a²b+ab²+a²b+2ab²+b³
=a³+3a²b+3ab²+b³
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If a=5x and b=-4y
(5x+(-4y))³
=(5x-4y)³
=(5x)³+3(5x)²(-4y)+3(5x)(-4y)²+(-4y)³
=125x³+3(25x²)(-4y)+15x(16y²)-64y³
=125x³+75x²(-4y)+240xy²-64y³
=125x³-300x²y+240xy²-64y³
There's no equation to solve, until you tell us
what that expression is equal to.
Answer:
15+6x=75
Step-by-step explanation:
15 is the starting fee and it is 6$ per class so it would be 6x+15=75
Answer:
multiply input number by 4
Step-by-step explanation:
In the figure attached, the problem is shown.
We can see the following values:
input = 1, output = 4*1 = 4
input = 4, output = 4*4 = 16
input = 7, output = 4*7 = 28
Then, the missing numbers can be found multiply input number by 4