Given:
The system Mx+Ny=P has a solution (1,3) where Rx+Sy=T; <span>M, N, P, R,S and T are non-zero real numbers.
Solve for M, N, R, P, S, T:
M +3N = P
R + 3S = T
The given choices should simplify to the equations above.
A) Mx +Ny = P
7Rx + 7Sy = 7T
7(Rx + Sy) = 7T
Rx + Sy = T
remarks: CORRECT
B) (M+R)x + (N+S)y = P + T
Rx + Sy = T
Mx + Rx + Ny + Sy = P + T
Mx + Ny + T = P + T
Mx + Ny = P
remarks: CORRECT
C) Mx + Ny = P
(2M - R)x + (2N - S)y = P - 2T
2Mx - Rx + 2Ny - Sy = P - 2T
2(Mx + Ny) - (Rx + Sy) = P - 2T
2P - (Rx + Sy) = P - 2T
remarks: INCORRECT
</span>
Answer:
y=0.75x + 1.25
Step-by-step explanation:
You just need to isolate y by transferring all the numbers to the other side of the equation (& the numbers with x)
Glad to help
Answer:
Step-by-step explanation:
we know that
The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side
In this problem
M is the mid-point segment AB
N is the mid-point segment BC
so
Applying the Midpoint Theorem
MN is parallel to AC
we have that
---> given problem
substitute
Answer:
angle V = 60 degrees
angle U = 90 degrees
angle W = 30 degrees
This is the last option
Explanation:
Part a: getting angle U:
Let's start by doing the Pythagorean check:
hypotenuse = sqrt [(side1)^2 + (side2)^2]
side1 = 3√3 and side2 = 3 cm
Substitute in the above equation:
hypotenuse = sqrt [ (3√3)^2 + (3)^2]
hypotenuse = 6 cm
This proves that the given triangle is right-angled at U
Therefore:
measure angle U = 90 degree
Part b: getting angle V:
cos theta = adjacent / hypotenuse
theta is angle V
adjacent side = 3 cm
hypotenuse = 6 cm
Therefore:
cos V = 3/6 = 1/2
V = 60 degrees
Part c: getting angle W:
We can get this using two methods:
Method 1:
Angles of triangle = 180
180 = 90 + 60 + angle W
angle W = 180 - (90+60) = 30 degrees
Method 2:
cos theta = adjacent / hypotenuse
theta is W
adjacent = 3√3 cm
hypotenuse = 6 cm
Therefore:
cos W = 3√3 / 6 = √3 / 2
W = 30 degrees
Hope this helps :)
