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DaniilM [7]
3 years ago
11

132 beads is split into 96 beads and 36 beads. in simplest form , what is the ratio of the split​

Mathematics
1 answer:
mars1129 [50]3 years ago
3 0

Answer:

16:6

Step-by-step explanation:

96:36

Highest common factor is 6

divide both sides by 6

16:6

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A
kondor19780726 [428]

Answer: 18.2

Step-by-step explanation:

14^{2}+b^{2}=23^{2}\\b^{2}=23^{2}-14^{2}\\b=\sqrt{23^{2}-14^{2}} \approx \boxed{18.2}

4 0
2 years ago
Please help me with domain and range of graphs Part 1​
dybincka [34]

Answer:

  • see the attached for domain
  • Range: (-∞, 4], [3, ∞), [-3, 1]

Step-by-step explanation:

The domain is the horizontal extent of the graph. When the graph has arrows on the end, it extends to infinity in the indicated direction.

__

The range is the vertical extent of the graph.

<u>Left Graph</u>

We assume the curve is intended to touch, not cross, the line y=4, so the range is ...

  range: (-∞, 4]

__

<u>Middle Graph</u>

We assume the graph continues along the line y=3 to the right indefinitely. Then this value is the minimum of the range.

  range: [3, ∞)

__

<u>Right Graph</u>

The low point on the graph is at y=-3, and it looks like the graph continues to the right along the line y=1. Then the range is ...

  range: [-3, 1]

8 0
3 years ago
3)<br> Solve the quadratic equation by taking square roots.<br> 3x^2 – 8 = 12
iris [78.8K]

Answer:

The answer is in the photo

Step-by-step explanation:

8 0
4 years ago
An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 100100 engin
Margaret [11]

Answer:

Null hypothesis:\mu \geq 7.3    

Alternative hypothesis:\mu < 7.3    

z=\frac{7.2-7.3}{\frac{0.81}{\sqrt{100}}}=-1.235    

p_v =P(z    

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so then we can conclude that the mean pressure for the automobile engines is not significantly less than 7.3 at 1% of significance.  

Step-by-step explanation:

1) Data given and notation    

\bar X=7.2 represent the sample mean    

\sigma=0.81 represent the population standard deviation    

n=100 sample size    

\mu_o =7.3 represent the value that we want to test    

\alpha=0.01 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean pressure is lower than the specificated value 7.3, the system of hypothesis are :    

Null hypothesis:\mu \geq 7.3    

Alternative hypothesis:\mu < 7.3    

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{7.2-7.3}{\frac{0.81}{\sqrt{100}}}=-1.235    

4) P-value    

Since is a one-side lower test the p value would given by:    

p_v =P(z    

5) Conclusion    

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean pressure for the automobile engines is not significantly less than 7.3 at 1% of significance.  

7 0
3 years ago
A retired auto mechanic hopes to open a rustproofing shop. Customers would be local new-car dealers. Two locations are being con
const2013 [10]

It is convenient to let a spreadsheet or graphing calculator do the math for this. Functions can be defined for cost and profit, and evaluated at each of the volumes of interest.

a1) For 200 cars, the Outside location yields the greatest profit

a2) For 300 cars, the City location yields the greatest profit

b) The sites yield the same profit for a volume of 278 cars.

3 0
3 years ago
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