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nasty-shy [4]
4 years ago
11

4.) You have made a model tree for you 1:64 scale railroad that is 20cm tall. How tall in real life would this tree be? (1 meter

=100 centimeters)
5.) A model battle ship you have just made is 2 feet long. The real thing is 350 feet long. What is the scale ratio between model and real life?

6.) A map has a scale of 1 inch equaling 20 miles.
a) On the map, how far would 5 inches be?
b) Chicago is 200 miles from Appleton. What is the distance on the map?
c) If this same map where large enough to include the whole world (25,000 miles at equator), how long would the map have to be? (12in=1ft).

7) A map has a scale of 1 inch equaling 2.5 miles.
a) On the map, how far would 5 inches be?
b) The Wiouwash Bike trail West of Appleton is 41 miles long. How far on the map is that?
c) is this a reasonable map to show the route between Appleton and Chicago? Why or why not?
Mathematics
1 answer:
Vadim26 [7]4 years ago
8 0
5. 1:175, if 2ft= 350 ft in life 1ft feet would probably be 175. (Cross multiplication)
6.a)100miles, 1 inch= 20mile so 5 inches multiplied by 20 miles gives you 100miles
b) 10 inches from Appleton. 1inch:20miles  (cross multiply to get 10inches)
                                                 x   :200miles
c)25000 miles will reach the equator so 50000 miles will go around the world! So, if 1inch:20miles,(50000/20=2500inches) And if 12inches:1ft, 2500inches * 1ft/12 inches to get 208.33.
7.a) 1inch:2.5miles(5inches*2.5miles/1) 5inches would be 12.5miles.
b)1inch:2.5miles, 41miles?. (1inch*41miles/2.5miles=x) x=16.4, so 41miles=16.4inches
c)No. Because they have different scales.

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MA_775_DIABLO [31]

Answer:

ans is d

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3 0
3 years ago
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melissa and brian are at the base of a moutain. melissa hikes to a location 27 meters above sea.level brian hikes to a location
sweet [91]

Answer:

The difference is 48 meters

Step-by-step explanation:

<u><em>The question is</em></u>

What is the difference of the hikers' altitudes?

Let

x -----> the Melissa's altitude in meters

y ----> Brian's altitude in meters

we have that

x=+27\ ft ---> is positive because is above sea level

y=-21\ ft ---> is negative because is below sea level

Remember that the sea level is the altitude equal to zero

<em>Find the difference</em>

To find out the difference of the hikers' altitudes, subtract Brian's altitude from Melissa's altitude

so

27-(-21)

Remember that (-1)(-1)=+1

27+21=48\ m

7 0
4 years ago
HELPP!!! Isn't one of the answers supposed to be 3?????
ikadub [295]

Step-by-step explanation:

well, it is supposed to be -3.

but you are right. something is wrong or missing here.

5x + 3 = 4x

x + 3 = 0

x = -3

maybe a "+ 1" is missing on the right side ?

5x + 3 = 4x + 1

gives us

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7 0
2 years ago
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Please help me please I don’t understand and my teacher said I got it wrong for numbers 1 2 and 3
kirza4 [7]

Answer:

1) 5/9

2) 4/7

3) 3/8

Step-by-step explanation:

1) 5/9

2) 4/7

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3 0
3 years ago
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In triangle ABC shown below, DE is parallel to AC. The following two-column proof with missing statements and reasons proves tha
lianna [129]

Answer:

The correct option is;

C. 3. ∠BDE ≅∠BAC, Corresponding Angles Postulate 4. ∠B ≅ ∠B Reflexive Property of Equality

Step-by-step explanation:

The two column proof can be written as follows;

Statement,                         Reason

1. \overline{DE} \parallel \overline{AC},                           Given

2. \overline {AB} is a transversal ,         Conclusion from statement 1.

We note that ∠BDE  and ∠BAC are on the same side of the transversal relative to the parallel lines, and are therefore, corresponding angles.

Therefore, we have;

3. ∠BDE ≅∠BAC,                 Corresponding Angles Postulate

Also

4. ∠B ≅ ∠B,                           Reflexive Property of Equality

In the two triangles, ΔABC and ΔDBE, we have ∠BDE ≅∠BAC and ∠B ≅ ∠B,

From ∠BDE + ∠B + ∠BED = 180°

∠BAC + ∠B +  ∠BCA = 180°

Therefore, ∠BED = ∠BCA Substitution property of equality

Which gives;

5, ΔABC ~ ΔDBE,          Angle Angle Similarity Postulate

6. BD/BA = BE/BC,      Converse of the Side-Side-Side Similarity Theorem

5 0
3 years ago
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