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Kazeer [188]
3 years ago
14

Please hurry I will mark you brainliest

Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0

Answer:

Here's the answers

Step-by-step explanation:

1. When two variables are in relation with a formula or a variable is related by the sum of two or more variables, then it is a partial variation. X = KY + C (where K and C are constants) is a straight line equation which is an example of partial variation.

2. The formula y=kxn y = k x n is used for direct variation. The value k is a nonzero constant greater than zero and is called the constant of variation.

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Write the interval (5,100] as an inequality and using set notation
drek231 [11]

Answer: { x | 5 < x ≤ 100 }  OR  { x ∈ ℝ | 5 < x ≤ 100 }

Step-by-step explanation:

{ x | 5 < x ≤ 100 }

This means:

"The set of all x's, such that x is greater than 5 and less than or equal to 100"

Another acceptable way to write this is

{ x ∈ ℝ | 5 < x ≤ 100 }

"x ∈ ℝ" simply means x is an element of all real numbers

7 0
3 years ago
Solve the inequality c – 5 ≥ 0.5 and graph the solutions.
sammy [17]
The answer is c ≥ 5.5
3 0
3 years ago
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sam decides to build a square garden if the area of the other garden is 9x^2 -24x +16 square feet what is the length of one side
Yuri [45]
<span>9x^2 -24x +16 can be factored into (3x-4)</span>²
the length of each side is 3x-4
4 0
4 years ago
What is 25% of 40? I need the answer quickly!! First gets 5 stars and a thank you!!
eimsori [14]

Answer:

The answer is 10

I hope this helped and please mark me as brainliest!

6 0
3 years ago
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In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Cal
soldier1979 [14.2K]

Given that,

Sample size= 83

Mean number= 39.04

Standard deviation= 11.51

We know the critical t-value for  95% confidence interval which is equal to 1.989.

We also know the formula for confidence interval,

CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))

So, we have

CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)

CI= (39.04 - 2.513,39.04 + 2.513)

CI= (36.527,41.553)

Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).

8 0
3 years ago
Read 2 more answers
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